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Luden [163]
2 years ago
11

A factory can build 20 cars every hour.what is the slope to show this?

Mathematics
1 answer:
Dmitrij [34]2 years ago
4 0

Answer:

A.) y = 20x

B.) 21 minutes

Step-by-step explanation:

y = mx + b;       y2 - y1/ x2 - x1 = m (slope)

A.) If a factory can build 20 cars per hour, the first point would be (1, 20). To find the slope (m), divide the y-axis by the x-axis: 20/1 = 20.

B.) Before we can do this problem, we must first convert the hours to minutes. 1 hour = 60 minutes. Then we divide the minutes by the number of cars. 60 ÷ 20 = 3. That means the factory builds 1 car every 3 minutes. Multiply the number of cars, 7, by the number of minutes it takes to make one car: 7 • 3 = 21.

Hope this helps,

♥<em>A.W.E.S.W.A.N.</em>♥

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Please need help on this
ser-zykov [4K]

Answer: In my answer I got 9 because the formula to find the area it would be A=1/2b*h



Step-by-step explanation: How would you do this?

Well we know that the base equals 6 we have heighth so we would have to do 1.5*6 and that would give us 9 but if we round it would be 10 because 9 is closer to 10 than it is to 0.


thanks :)


4 0
3 years ago
Can someone help me solve this???
Vlad [161]
Answer: b

Explanation: cube root is equal to the power of 1/3
Multiply the exponents 24/3=8
3 0
3 years ago
Read 2 more answers
Need help asap!!!30 POINTS!!!!!
OlgaM077 [116]

Answer:

What is it?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help me please explain on how to do this
Leviafan [203]

Answer:

Easy

Step-by-step explanation:

To find the perimeter, add all the sides together.

12+16+20=48

To find the area, you multiply the sides that make the right angle of the triangle,

12×16=192

And divide it by two. This step is important as if you don't divide it by two, you will end up with the area of a square.

192÷2=96

Finito. Oh and don't forget to add units.

Cm for perimeter and Cm(squared) for area. :)

7 0
2 years ago
Given that y=x^(1/3) , use calculus to determine an approximate value for ∛8030
Alex777 [14]
F(x) = x^(1/3)
f(8000) = 8000^(1/3) = 20

f'(x) = 1/3 * x^(-2/3)
f'(x) = 1/(3x^(2/3))
f'(8000) = 1/(3*8000^(2/3)) = 1/(3*400) = 1/1200

Linear approximation for f(x) about x = 8000
L(x) = f(8000) + f'(8000) (x−8000)
L(x) = 20 + 1/1200 (x−8000)

8030^(1/3) ≈ L(8030)
= 20 + 1/1200 (8030−8000)
= 20 + 30/1200
= 20 + 1/40
= 20.025
8 0
2 years ago
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