Pakisagutan po pls help me
1 answer:
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Given that , and
, this first step can be to make the equations equivalent to one another. As you can see, each equation is equal to a constant, e. Therefore, we can conclude that the equations can be equal to one another as well ( transitivity ).
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Nice and simple question we have here! The step that can be used to find the solution should be .
Answer: Probability of trucks having both defects is 4%.
Step-by-step explanation:
Since we have given that
Probability of trucks having defective brake linings only = 6%
Probability of trucks having defective steering only = 3%
Probability of trucks having neither defect = 87%
Probability of trucks having either defect - 100 - 87 = 13%
Let the probability of trucks having both defects be 'x'.
P(defective brake lining) = P(B) = 0.06+x
P(defective steering) = P(S) = 0.03+x
So, Probability of the trucks having both defects is given by
So, Probability of trucks having both defects is 4%.