Answer:
x = 0 , 2/3
Step-by-step explanation:
3x^3-x^2=x^2
3x^3-2x^2=0
x^2(3x-2)=0
Now split into two equations:
1)
x^2=0
x=0
2)
3x-2=0
3x=2
x=2/3
Factor:
3x^2 + 27
= 3(x^2 + 9)
Answer is 3(x^2 + 9), when factored.
A) (3x + 9i)(x + 3i)
= (3x + 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
= 3x^2 + 9ix + 9ix + 27i^2
= 27i^2 + 18ix + 3x^2
B) (3x - 9i)(x + 3i)
= (3x + - 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + ( - 9i)(x) + (- 9i)(3i)
= 3x^2 + 9ix - 9ix - 27i^2
= 27i^2 + 3x^2
C) (3x - 6i)(x + 21i)
= (3x + - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
= 3x^2 + 63ix - 6ix - 126i^2
= - 126i^2 + 57ix + 3x^2
D) (3x - 9i)(x - 3i)
= (3x + - 9)(x + - 3)
= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
= 3x^2 - 9ix - 9x + 27i
= 9ix + 3x^2 + 27i - 9x
Hope that helps!!!
The number would stay the same because, for example, 6 - 0 can't be 0 so it would be 6.
Answer: 
unit
Step-by-step explanation:
Since Here Δ ABC is a isosceles triangle.
Also, 
and 
Thus, ∠ ADH = 90°
That is, Δ ADH is the right angle triangle.
In which, AD = a unit and HD = b unit
And, By the definition of Pythagoras theorem,
⇒ 
⇒ 
Since, the perimeter of a triangle = sum of the all sides of the triangle.
Therefore, perimeter of ΔADH = AD + DH + AH
= 
unit
