Answer:
x = a(c - b)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Step-by-step explanation:
<u>Step 1: Define Equation</u>
x/a + b = c
<u>Step 2: Solve for </u><em><u>x</u></em>
- Subtract <em>b</em> on both sides: x/a = c - b
- Multiply <em>a</em> on both sides: x = a(c - b)
Answer:
₹40000, 66.6%
Step-by-step explanation:
Given data
Number of boxes= 50
Cost per box= ₹1200
Total cost= 50*1200= ₹60000
Total number of mangoes in all 50 boxes= 50*100= 5000 mangoes
Cost price per mago= 60000/5000= ₹12
Selling price per mango= ₹20
profit = selling price- cost price
profit= 20-12
proft= ₹8
Total profit = 8*5000
Total profit= ₹40000
%profit = 40000/60000*100
%profit= 0.666*100
%profit= 66.6%
Answer:
B
Step-by-step explanation:
since y and x vary directly the equation relating them is
y = kx ← k is the constant of variation
to find k use any ordered pair from the list given
using x = 4 when y = - 2, then
k =
=
= - 0.5 → B
Answer:
D. The company's chocolate bars weigh 3.2 ounces on average.
Step-by-step explanation:
We are given that a company claims that its chocolate bars weigh 3.2 ounces on average.
The company took many large samples, and each time the mean weight of the sample was within the 95% confidence interval.
Definition of 95% confidence level: 95% confidence level means a range of values that you can be 95% certain contains the true mean of the population.
Thus by considering definition we can conclude that The company's chocolate bars weigh 3.2 ounces on average.
Thus Option D is correct.
D. The company's chocolate bars weigh 3.2 ounces on average.
Answer:
$4
Step-by-step explanation:
The two purchases can be written in terms of the cost of an adult ticket (a) and the cost of a student ticket (s):
7a +16s = 120 . . . . . . . . price for the first purchase
13a +9s = 140 . . . . . . . . price for the second purchase
Using Cramer's rule, the value of s can be found as ...
s = (120·13 -140·7)/(16·13 -9·7) = 580/145 = 4
The cost of a student ticket is $4.
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<em>Comment on Cramer's Rule</em>
Cramer's rule is particularly useful for systems that don't have "nice" numbers that would make substitution or elimination easy methods to use. If you locate the numbers in the equation, you can see the X-patterns that are used to compute the numerator and denominator differences.
The value of a is (16·140 -9·120)/(same denominator) = 1160/145 = 8. I wanted to show you these numbers so you could see the numerator X-pattern for the first variable.
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Of course, graphical methods can be quick and easy, too.