Answer:
Step-by-step explanation:
Eliminate answer 4 immediately, because (4)(3) is not 7.
Look at answer 2: 7x + 3x = 10x, which does not match the middle term 12x in the original polynomial. Eliminate answer 2.
Look at answer 1: 1x + 21x = 22x, which does not match the middle term of the original polynomial. Eliminate answer 1.
All quadratics have solutions. Let's apply the quadratic formula to 3x^2 + 12x + 7: Here a = 3, b = 12 and c = 7, so that the discriminant b²-4ac is
12²-4(3)(7), or 144 - 84, or 60. Being positive, this tells us that the given poly has two real, unequal roots:
-12 ± √60 -12 + 2√15 -12 - 2√15
x = ----------------- = ------------------- and x = --------------------
3 3 3
Normally, if c is a root, then x - c is a factor.
If we try this here, however, the resulting factors do not at all match any of your answer choices.
Don't be offended...but please ensure you have copied this problem down correctly.
the discriminant formula is b^2-4ac
so plug the values from each equation into the formula and solve, the result is the value of the discriminant
if the number is negative, there are no real roots/x-int
if it is 0 there is one real root/x-intercepts
if it is positive it has 2 real roots/x-int
and to find the actual solutions you have to plug the values into the quadratic formula
I don't know if this is right or not but I think the coordinates at the angle on the circular protractor so for a) if you (114-62) you should get the answer, for b)if you (62+40) you should get the answer, for c) if you [114-(62+40)] you should get the answer.
Answer:
y = -2
Step-by-step explanation:
The midline is the horizontal line that passes exactly in the middle between the graph's maximum and minimum points.
From inspection, curve has a maximum at y = 1 and a minimum at y = -5
The midline between these is 
So the equation for the midline of this graph is y = -2 (shown in red on the attached graph)
1:3 = 16/48 and 1/3.
Have a nice day! :D
