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2 years ago

Is 7.8 cm, 1.1 cm, 9.1 cm a triangle

1 answer:

5 0

Answer: The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Since, 11 + 21 > 16, 11 + 16 > 21, and 16 + 21 > 11, you can form a triangle with side lengths 11 mm, 21 mm, and 16 mm.

Step-by-step explanation:

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How do you simplify the radical expression, 24- sqrt(720 over 4

baherus [9]

24- sqrt(720/4) divide 720 by 4

24 - sqrt (180) now break down 180 to 9*4*5

24- sqrt(9) *sqrt(4) *sqrt (5) so 9becomes 3, 4 becomes 2

24- 3*2*sqrt(5) multiply 3 and 2

24-6sqrt(5)

7 0

3 years ago

Can someone help me please

Nat2105 [25]

Ithe diameter would be about 5

4 0

2 years ago

Read 2 more answers

Use elimination to solve<br><br> 3y-6x=7-4y-3x=9

Masja [62]

Reorder both sides

3y-6x=9
7-4y-3x=9

Multiply both sides
-6x-3y=9
6x+8y=-4

Dived both sides

11y= 5

Y=5/11

Substitute the value of Y

-3x-4(5/11)

Equals —> -14/11

Answer : (5/11 , -14/11)

5 0

2 years ago

A used car dealer has 30 cars and 10 of them are lemons (i.e.~ mechanically faulty used cars), and you don't know which is which

Triss [41]

Answer: Hence, the probability that he will get at least one lemon is 0.70.

Step-by-step explanation:

Since we have given that

Number of cars = 30

Number of lemon cars = 10

Number of other than lemon cars = 30-10 = 20

According to question, he bought 3 cars,

we need to find the probability that you will get at least one lemon.

So, P(X≤1)=1-P(X=0)=1-P(no lemon)

Here, P(no lemon ) is given by

$\dfrac{20}{30}\times \dfrac{20}{30}\times \dfrac{20}{30}=(\dfrac{20}{30})^3$

so, it becomes,

$P(X\geq 1)=1-(\dfrac{20}{30})^3=1-(0.67)^3=0.70$

Hence, the probability that he will get at least one lemon is 0.70.

5 0

3 years ago

Six dogs give birth to 4 puppies each. Half of those puppies are female and go on to have 4 puppies each of their own. How many

SOVA2 [1]

Easy, the answer is 12

5 0

3 years ago