Answer:
3x+y=8 and 3x+y=9
Step-by-step explanation:
Assume these two equations:
a1x+b1y+c1=0
a2x+b2y+c2=0
If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.
In these case, take a look at the last option:
Re-write 'em as a standard form:
So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:
And they do not have any collision point
Answer:
x = 11
Step-by-step explanation:
4 - 1 / x - 7 (simplify)
3 / x - 7 = 3/4 (multiply by x - 7)
3 = 3/4 (x - 7)
3 = 3/4x - 5.25 (add 5.25 to both sides)
8.25 = 3/4x (divide both sides by 8.25)
x = 11
sub into the formula to check:
4-1 / 11 - 7
3 / 4
Y = kx
k = y/x
k = 2/12
k = 1/6
so when x = 12
y = kx
y = 1/6(5)
y = 5/6
answer
when x = 5 y = 5/6
28 x 25 = $700
Answer: The class raises at least $700.
