Given : In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product, 260 of these people said they never did so.

i.e. n= 1000 and x= 260

⇒ Sample proportion : $\hat{p}=\dfrac{260}{1000}=0.26$

z-value for 95% confidence interval : $z_c=1.960$

Now, an upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate. :-

$\hat{p}+ z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$=0.26+ (1.96)\sqrt{\dfrac{0.26(1-0.26)}{1000}}$

$=0.26+ (1.96)(0.01387)=0.26+0.0271852=0.2871852\approx0.2872$

∴ An upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate : 0.2872

7 0

3 years ago

Mariah’s parents got into a car accident. They took their car to the

KatRina [158]

Answer: The mechanics spent about 8.5 hours working on the car

Step-by-step explanation: The total bill was $637, a portion of that being getting the parts which was $280. 637-280=357

357/42=8.5

5 0

2 years ago

How can I simplify this equation ​

How can I simplify this equation