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Viktor [21]
3 years ago
13

3. A researcher studied the eyesight of people at different ages. She calculated a vision score for each person in the study and

plotted the data on the graph below. The researcher used the line y = -0.1 x +110 to model the data.
A)When the researcher substituted the value of x = 65 into this equation, what is the resulting y value (vision score)?




B)Based on the coordinates of the given data points, what is the actual actual vision score when x=65?




C)When the researcher substituted x = 65 into the line of equation, is the resulting y value the predicted value or the exit value for the vision score of a 65-year-old? Use your results for parts a and b to answer this question.

Mathematics
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

A)Predicted value = 103.5

B)Actual value = 102

C)So, these are not same

Step-by-step explanation:

The researcher used the liney = -0.1 x +110 to model the data.

A)When the researcher substituted the value of x = 65 into this equation, what is the resulting y value?

Substitute value x=65 in equation :

y = -0.1 x +110

y=-0.1(65)+110

y=103.5

Predicted value = 103.5

B)Based on the coordinates of the given data points, what is the actual actual vision score when x=65?

Use the given graph

When x = 65

y = 102

So, The actual actual vision score when x=65 is 102

C)When the researcher substituted x = 65 into the line of equation, is the resulting y value the predicted value or the exit value for the vision score of a 65-year-old? Use your results for parts a and b to answer this question.

Predicted value = 103.5

Actual value = 102

So, these are not same

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Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f
schepotkina [342]

Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval:  (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{130}{20} = 6.5

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

S.D = \sqrt{\frac{233.5}{19}} = 3.50

b) Standard Error

= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826

c) Point estimate for the mean time required for all college is given by the sample mean.

\bar{x} = 6.5

d) 90% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729  

6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

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Answer:

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Step-by-step explanation:

Convert fraction (ratio) 25 / 100 Answer: 25%

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