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3 years ago

Music Read aloud 1) Sound effects

Mathematics

2 answers:

zvonat [6]3 years ago

4 0

Answer:

Step-by-step explanation:

What am I supposed to do? If you don’t mind me asking. Like I’m not trying to waste your points at all just I’m confused I can def help tho if you tell me what I need to do

Marysya12 [62]3 years ago

4 0

Answer:

Huh-?

Step-by-step explanation:

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Please help with this question its in the picture

svlad2 [7]

Answer:

the answer is A

Step-by-step explanation:

3 0

4 years ago

Which would neatly fill the gap in the prism shown below? Check all that apply. A prism has a length of 2 and one-half, height o

Simora [160]

Answer:

12 blocks each measuring One-fourth times 1 times 1 and6 blocks each measuring one third times one time 1

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The best way to solve the equation log 6 (6)^7 = x is

dybincka [34]

Answer:

(A) put the 7 in front of the log

log 6 (6)^7 = x

7 * log 6 (6) = x

7 * 1 = x

x = 7

6 0

4 years ago

What is the minimum of the sinusoidal function?

lina2011 [118]

Answer:

The minimum of the sinusoidal function is -4

Step-by-step explanation:

The given sinusoidal function has an amplitude of 4.

The range of the given sinusoidal function is $-4\le y\le 4$ .

The minimum value is the least y-value of the range which is -4.

The minimum is therefore -4.

7 0

4 years ago

Mathematics 13 don’t understand

UNO [17]

Answer:

1/6^3

Step-by-step explanation:

The applicable rules of exponents are ...

a^-b = 1/a^b

(a^b)(a^c) = a^(b+c)

Your expression can be simplified as follows:

$\dfrac{6^{-5}}{6^{-2}}=\dfrac{1}{(6^{-2})(6^5)}=\dfrac{1}{6^{-2+5}}=\boxed{\dfrac{1}{6^3}}$

_____

<em>Additional comment</em>

If you think of an exponent as signifying repeated multiplication, the rules of exponents may be easier to remember. The exponent tells you how many times the base is a factor in the product.

Consider multiplication:

$(x\cdot x\cdot x)\cdot(x\cdot x)=x^3\cdot x^2=x^{3+2}=x^5\\\\(x\cdot x\cdot x)\cdot(x\cdot x\cdot x)=(x^3)^2=x^{3\cdot2}=x^6$

Consider division:

$\dfrac{x\cdot x\cdot x}{x\cdot x}=x\quad\Longleftrightarrow\quad\dfrac{x^3}{x^2}=x^{3-2}=x^1\\\\\dfrac{x\cdot x}{x\cdot x\cdot x}=\dfrac{1}{x}\quad\Longleftrightarrow\quad\dfrac{x^2}{x^3}=x^{2-3}=x^{-1}$

This may help you see that a positive exponent in the denominator is equivalent to a negative exponent in the numerator (and vice versa).

6 0

3 years ago