Step-by-step explanation:
When it says x = something, that basically means to replace the x with whatever it says x equals.
x = 0. Equation /. 3 x 0 = 0 + 1 = 1. Y = 1
x = -1. Equation/. 3 x -1 = -3 + 1 = -2. Y = -2
x = 2. Equation/. 3 x 2 = 6 + 1 = 7. Y = 7
Hope this helps!! (:
Answer:
2 x 10 x 4 + (4 + 10) x 2 x 6 = 80 + 168 = 248
Let's work on the left side first. And remember that
the<u> tangent</u> is the same as <u>sin/cos</u>.
sin(a) cos(a) tan(a)
Substitute for the tangent:
[ sin(a) cos(a) ] [ sin(a)/cos(a) ]
Cancel the cos(a) from the top and bottom, and you're left with
[ sin(a) ] . . . . . [ sin(a) ] which is [ <u>sin²(a)</u> ] That's the <u>left side</u>.
Now, work on the right side:
[ 1 - cos(a) ] [ 1 + cos(a) ]
Multiply that all out, using FOIL:
[ 1 + cos(a) - cos(a) - cos²(a) ]
= [ <u>1 - cos²(a)</u> ] That's the <u>right side</u>.
Do you remember that for any angle, sin²(b) + cos²(b) = 1 ?
Subtract cos²(b) from each side, and you have sin²(b) = 1 - cos²(b) for any angle.
So, on the <u>right side</u>, you could write [ <u>sin²(a)</u> ] .
Now look back about 9 lines, and compare that to the result we got for the <u>left side</u> .
They look quite similar. In fact, they're identical. And so the identity is proven.
Whew !
- I think it's possibly this "The figure must be a square because the diagonals of a square bisect the right angles." but there's also "The figure must be a rhombus because it has exactly 2 pairs of congruent angles." buuut since the first one seems more better i'm assuming then that's probably the right answer.
The domain is the value of x. In this case, -3≤x≤7
the range is the value of y. in this case, -1≤y≤9
this is not a function, because the same x value has two corresponding y values. For example, when x=5, y=0 or y=8
It IS a function if every x value has only one corresponding y value.