All categories

3 years ago

9 of 12

Mathematics

1 answer:

Deffense [45]3 years ago

7 0

Answer:

40 flapjacks

Step-by-step explanation:

Given the recipe :

Recipe: Makes 10 flapjacks

120 g margarine

100 g sugar

150 mL syrup

225 g oats

40 g sultanas

Given that all other ingredients are kept Constant.

225g of oats produces 10 flapjacks

0.9 kg of oat = 0.9 * 1000 = 900g oat

If :

225 g = 10 flapjacks

900 g = x

Cross multiply :

225x = 900 * 10

225x = 9000

x = 9000 / 225

x = 40

40 flapjacks

You might be interested in

When Johan calculates how much interest he must pay, he calculates as follows: SEK 0.045-620,000 = SEK 6,975/4

ryzh [129]

Answer:

its b

Step-by-step explanation:

7 0

3 years ago

What is the distance between the points (2, 1) and (14, 6) on a coordinate

ipn [44]

Answer: 13 units

Step-by-step explanation:

6 0

3 years ago

What are the next three terms -14,-9,-4

Serggg [28]

-28, -18, -8 ehhheheheeheh

5 0

3 years ago

PLease answer !!! Find constants $A$ and $B$ such that \[\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}\] for all

Xelga [282]

Answer:

1. $(A,B) = (3,-2)$

2. The values of t are: -3, -1

Step-by-step explanation:

Given

$\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

$|t| = 2t + 3$

Required

Solve for the unknown

Solving $\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

Take LCM

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{(x - 2)(x-1)}$

Expand the denominator

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - 2x + x -2}$

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - x -2}$

Both denominators are equal; So, they can cancel out

$x + 7 = A(x+1) + B(x-2)$

Expand the expression on the right hand side

$x + 7 = Ax + A + Bx - 2B$

Collect and Group Like Terms

$x + 7 = (Ax + Bx) + (A - 2B)$

$x + 7 = (A + B)x + (A - 2B)$

By Direct comparison of the left hand side with the right hand side

$(A + B)x = x$

$A - 2B = 7$

Divide both sides by x in $(A + B)x = x$

$A + B = 1$

Make A the subject of formula

$A = 1 - B$

Substitute 1 - B for A in $A - 2B = 7$

$1 - B - 2B = 7$

$1 - 3B = 7$

Subtract 1 from both sides

$1 - 1 - 3B = 7 - 1$

$-3B = 6$

Divide both sides by -3

$B = -2$

Substitute -2 for B in $A = 1 - B$

$A = 1 - (-2)$

$A = 1 + 2$

$A = 3$

Hence;

$(A,B) = (3,-2)$

Solving $|t| = 2t + 3$

Because we're dealing with an absolute function; the possible expressions that can be derived from the above expression are;

$t = 2t + 3$ and $-t = 2t + 3$

Solving $t = 2t + 3$

Make t the subject of formula

$t - 2t = 3$

$-t = 3$

Multiply both sides by -1

$t = -3$

Solving $-t = 2t + 3$

Make t the subject of formula

$-t - 2t = 3$

$-3t = 3$

Divide both sides by -3

$t = -1$

<em>Hence, the values of t are: -3, -1</em>

7 0

3 years ago

Read 2 more answers

What number is more than seven hundred two thousand, eight -three?

PSYCHO15rus [73]

2 million other words 2,000,000.

4 0

3 years ago

Read 2 more answers