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vodomira [7]
3 years ago
11

PLEASE HELP ASAP <3 Express as a trinomial (3x+5) (x+1) :)

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

3x²+8x+5

Step-by-step explanation:

Hi there!

We're given the product of two binomials: (3x+5)(x+1) and we want to express as a trinomial (polynomial with 3 terms)

we can multiply using FOIL; firsts, outers, inners, and lasts

Let's start by multiplying the firsts, which are the first terms in the two binomials, which are (3x+5) and (x+1)

So we'll multiply:

3x*x=3x²

Now we'll multiply the outers, which are the terms on the "outside" in the binomials, which are (3x+5) and (x+1)  (remember to include the sign!)

So we'll multiply:

3x*1=3x

then we'll multiply the inners, which are the terms on the "inside" of the binomials, which are (3x+5) and (x+1)

So we'll multiply:

5*x=5x

finally, we'll multiply the lasts, which are the last terms in the binomials, or (3x+5) and (x+1)

So we'll multiply:

5*1=5

now let's add up everything:

3x²+5x+3x+5

we have some like terms that we can combine

<u>3x²+8x+5</u>

Hope this helps!

Gennadij [26K]3 years ago
3 0

Answer:

3x^2+8x+5

Step-by-step explanation:

(3x+5)(x+1)

3x(x+1)+5(x+1)        Distribute

3x(x+1)+5(x+1)        Distribute 3x(x+1)

3x^2+3x+5(x+1)        

3x^{2} +3x+5(x+1)         Distrbute 5(x+1)

3x^2+3x+5x+5            Combine like terms

3x^{2} +8x+5

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Step-by-step explanation:

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Answer:

Let's solve for a.

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adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

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=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

a=

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

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