$\bf (\stackrel{x_1}{14}~,~\stackrel{y_1}{-8})\qquad (\stackrel{x_2}{24}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{(-8)}}}{\underset{run} {\underset{x_2}{24}-\underset{x_1}{14}}}\implies \cfrac{-3+8}{10}\implies \cfrac{5}{10}\implies \cfrac{1}{2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-8)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{14}) \\\\\\ y+8=\cfrac{1}{2}x-7\implies y=\cfrac{1}{2}x-15$

4 0

3 years ago

Match the statements in the table with the words/phrases contained in the word bank<br> Word Bank:

kykrilka [37]

Answer:

Circumcenter Incenter Centroid

Formed by intersection of Perp. Bisectors Angle bisectors Medians

Type of circle Circumscribed Inscribed No circle

Special property Equidistant from Equidistant from Center of mass

vertices Sides

6 0

3 years ago

WILL MARK AS BRAINLIEST IF CORRECT!

yuradex [85]

Answer:

Your answer is A:5

3 0

3 years ago