Ask question

Ask question

All categories

2 years ago

8

Which ordered pair could be removed from the graph to create a set of ordered pairs that represents a function? (–4, 2) (–1, 4)

(1, 3) (2, –3)

1 answer:

shepuryov [24]2 years ago

3 0

(-4, 2) is the pair that could be removed

You might be interested in

P and q are different two-digit prime numbers with the same digits, but in reversed order. what is the value of the larger of p

serious [3.7K]

The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}

Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original

If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap

8 0

2 years ago

Read 2 more answers

Mai will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $59.96 and costs an a

juin [17]

Answer:

600 miles.

Step-by-step explanation:

So basically we can write both plans as linear functions:

F(x) = $59.96+$0.14 . x

S(x) = $71.96+$0.12 . x

Where F(x) is the first plan, S(x) is the second one and X are the miles driven.

To know how many miles does Mai need to drive for the two plans to cost the same, we equalize both equations and isolate x.

F(x) = S (x)

$$59.96+$0.14.x = $71.96+$0.12.x \\0.14x-0.12x=71.96-59.96\\0.02x=12\\x=12 : 0.02\\x= 600$

Mai has to drive 600 miles for the two plans to cost the same-

4 0

2 years ago

Changle. Show all work. Round each length to the nearest tenth and each angle to the

Sedaia [141]

Answer:

Part 1) $BC=12.2\ units$

Part 2) $m\angle A=55^o$

Part 3) $m\angle C=35^o$

Step-by-step explanation:

Part 1) Find AC

we know that

In the right triangle ABC of the figure

Applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=7^2+10^2$

$AC^2=149\\AC=12.2\ units$

Part 2) Find the measure of angle A

we know that

In the right triangle ABC

$tan(A)=\frac{BC}{AB}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{10}{7}$

using a calculator

$m\angle A=tan^{-1}(\frac{10}{7})=55^o$

Part 3) Find the measure of angle C

we know that

In the right triangle ABC

$m\angle A+m\angle C=90^o$ ----> by complementary angles

substitute the given value

$55^o+m\angle C=90^o$

$m\angle C=90^o-55^o=35^o$

8 0

2 years ago

Name two angles with identical measures<br><br> A. B. C. D.

Semmy [17]

Angle POQ and Angle UOT are identical. This also applies to angles QOP and TOU, as they are the same angles as listed before.

7 0

2 years ago

Read 2 more answers

2(5-3v)+9v=28 step by step please

Irina-Kira [14]

First, distribute the 2 across the parenthesis.
10-3v+9v=28
Combine like terms on the left.
10+6v=28
Start to get the numbers on the right and the v alone on the left by moving the 10 to the right.
6v=28-10
6v=18
Divide to get the v alone.
v=3

Hope that helps.

4 0

2 years ago