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Mathematics

1 answer:

uranmaximum [27]3 years ago

4 0

120 in 1 minute 600 in 5 minutes and 960 in 8 minutes

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Help math question derivative!

atroni [7]

Let $f(x)=\sec^{-1}x$ . Then $\sec f(x)=x$ , and differentiating both sides with respect to $x$ gives

$(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1$
$f'(x)=\dfrac1{\sec f(x)\tan f(x)}$

Now, when $x=\sqrt2$ , you get

$(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}$

You have $\sec^{-1}\sqrt2=\dfrac\pi4$ , so $\sec\left(\sec^{-1}\sqrt2\right)=\sqrt2$ and $\tan\left(\sec^{-1}\sqrt2\right)=1$ . So $(\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}$

5 0

3 years ago

I need to find the surface area on questions 1-8 , please help!

ser-zykov [4K]

Answer:

2.486

3.1734

4.726

5.1350

6.canot see number in picture

7.864

8.54

Step-by-step explanation:

4 0

3 years ago

Match each point label on the box it to its description.

Ahat [919]

A is the minimum value
B is the first quartile
The point with the line through it (next to C) is the median.
The point to the outside of the box is the third quartile.
D is the maximum value.

Hope this helped.

4 0

3 years ago

The table shows ordered pairs of the function y = 16 0. 5x. A 2-column table with 6 rows. The first column is labeled x with ent

zvonat [6]

Option 3 is the correct answer. The missing values of (x, y) is (8, 20).

<h3>How do you find out the values?</h3>

Given that the function is,

$y = 16 + 0.5x$

The function is a linear equation that can be solved graphically. The values of both variables x and y can be found on different points along with the straight-line graph.

Also, for every value of x, there is a corresponding value of y.

For the given options, we put the values of x to find the corresponding value of y.

For option 1, put x = 0 in the given function,

$y = 16 + 0.5\times 0\\y = 16$