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3 years ago

Write the equation of the line in slope intercept form if its slope is 3 and y intercept is -5

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

7 0

Answer:

y = 3x - 5

Step-by-step explanation:

1. The slope-intercept form a line is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept.

2. Given the values of m and b, let's plug them in:

$y = (3)x+(-5)$
$y = 3x-5$

Therefore, the equation of the line in slope-intercept form is y = 3x - 5.

Have a lovely rest of your day/night.

Archy [21]3 years ago

3 0

Y = mx + b is the slope formula

in this case:

b = -5
m= 3

Therefore the slope formula form of this equation is

y = 3x - 5

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Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

blsea [12.9K]

Answer:

a) Percentage of students scored below 300 is 1.79%.

b) Score puts someone in the 90th percentile is 638.

Step-by-step explanation:

Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

(a) If the average test score is 510 with a standard deviation of 100 points.

To find : What percentage of students scored below 300 ?

Solution :

Mean $\mu=510$ ,

Standard deviation $\sigma=100$

Sample mean $x=300$

Percentage of students scored below 300 is given by,

$P(Z\leq \frac{x-\mu}{\sigma})\times 100$

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Percentage of students scored below 300 is 1.79%.

(b) What score puts someone in the 90th percentile?

90th percentile is such that,

$P(x\leq t)=0.90$

Now, $P(\frac{x-\mu}{\sigma} < \frac{t-\mu}{\sigma})=0.90$

$P(Z< \frac{t-\mu}{\sigma})=0.90$

$\frac{t-\mu}{\sigma}=1.28$

$\frac{t-510}{100}=1.28$

$t-510=128$

$t=128+510$

$t=638$

Score puts someone in the 90th percentile is 638.

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