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Stolb23 [73]
3 years ago
11

Find the value of (3^0+4^-1)×2^2 ​

Mathematics
2 answers:
nadya68 [22]3 years ago
6 0
(3⁰+4-¹) × 2²

= (1 + ¹/₄ ) × 4

= ⁵/₄ × 4

= 20
wariber [46]3 years ago
3 0

Answer:

Solution

=(1+0.25)×4

=1.25×4

=5

since 3^0=1

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F(n) = 25
g(n) = 3(n - 1)
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2. From the top of a vertical cliff 40 m high, the object is 59.3m from the base of the cliff. Find the angle of depression to t
ArbitrLikvidat [17]

34^{\circ} is the angle of depression from the vertical cliff.

Option: A

Step-by-step explanation:

Given that, Height of the cliff (opposite side) = 40m

Distance of object from the base of the cliff (adjecent side)  = 59.3m

To find the angle of depression of the object. From trigonometric rule in a right angled triangle, we know that \tan \theta=\frac{\text { opposite side }}{\text { adjecent side }} \theta=\tan -1 \frac{\text { opposite side }}{\text { adjecent side }} Angle of depression = \tan -1 \frac{\text { height of cliff }}{\text { Distance of object from the base of the cliff }}=\tan ^{-1} \frac{40}{59.3}=34^{\circ} Therefore, the angle of depression to the object is 34^{\circ}.

3 0
4 years ago
If f(x) = 6x - 4 and g(x) = 2x^3, find g(3) - f(4)
Korolek [52]

To solve the problem, simply plug in the value for x in both functions, as shown below:

f(4) = 6(4) - 4

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g(3) - f(4) = 54 - 20, so the answer is 34.

7 0
4 years ago
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