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motikmotik
3 years ago
14

Which of the following is the correct algebraic representation of the translation below?

Mathematics
1 answer:
Sliva [168]3 years ago
7 0
The answer is D because it went up five then right 6
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My divisor is 4/7 and my quotient is 7/24. what is the dividend
kompoz [17]

Answer:

1/6.

Step-by-step explanation:

x / 4/7 = 7/24  where x is the dividend.

7x/4  = 7/24

Cross multiply:

7x * 24 =  4*7

x = 28/(7*24)

= 28/168

= 1/6.

3 0
3 years ago
My question is ...champ is 1st in a race star is 3rd and Pom is 4th if 2 more horses pass star what place will Pom be in? HELP P
Ad libitum [116K]
Pom would be in 6th place

3 0
4 years ago
If 2 is added to both the numerator and denominator of a fraction its value becomes half. If two is subtracted from both the num
Hitman42 [59]

Answer:

The original fraction is \frac{6}{14}.

Step-by-step explanation:

Solution,

Let the fraction be'\frac{x}{y}'.

Where 'x' is the numerator and 'y' is the denominator.

Now according to question, if 2 is added to both the numerator and denominator the value of the fraction becomes 1/2.

So, framing the above sentence in equation form, we get;

\frac{x+2}{y+2}=\frac{1}{2}

On using cross multiplication method, we get;

2(x+2)=y+2\\\\2x+4=y+2\\\\2x+4-2=y\\\\\therefore\ y=2x+2\ \ \ \ equation\ 1

Now according to question, if 2 is Subtracted to both the numerator and denominator the value of the fraction becomes 1/3.

So, framing the above sentence in equation form, we get;

\frac{x-2}{y-2}=\frac{1}{3}

On using cross multiplication method, we get;

3(x-2)=y-2\\\\3x-6=y-2\\\\3x-y=-2+6\\\\3x-y=4 \ \ \ \ equation\ 2

Now Substituting the equation 1 in equation 1 we get;

3x-y=4\\\\3x-(2x+2)=4\\\\3x-2x-2=4\\\\3x-2x=4+2\\\\x=6

Now Substituting the value of x in equation 1 we get;

y=2x+2\\\\y=2\times6+2 = 14

Hence The original fraction is \frac{6}{14}.

4 0
3 years ago
-4.67 + (5.24 – <br> ) – (<br> + 7.98) = 13.26
Vadim26 [7]

Answer:

6

Step-by-step explanation:

8 0
2 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
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