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Georgia [21]
3 years ago
8

The sum of two consecutive interegers is -131. Find the larger number.

Mathematics
1 answer:
Reika [66]3 years ago
6 0
a,a+1- two\ consecutive\ integers\\\\
a+a+1=-131\\\\
2a+1=-131\ \ \ | subtract\ 1\\\\2a=-132 \ \ \ | divide\ by\ 2\\\\
a=-66\\\\
Numbers\ are:\ -66,-65.
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Given in the question the function

f(x)=10-x^2

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domain = set of all integers

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since any negative value of x will be positive with squared so we will start from 0

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