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Georgia [21]
3 years ago
8

The sum of two consecutive interegers is -131. Find the larger number.

Mathematics
1 answer:
Reika [66]3 years ago
6 0
a,a+1- two\ consecutive\ integers\\\\
a+a+1=-131\\\\
2a+1=-131\ \ \ | subtract\ 1\\\\2a=-132 \ \ \ | divide\ by\ 2\\\\
a=-66\\\\
Numbers\ are:\ -66,-65.
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Determine the two ordered pair solutions of the equation y = 2x2 + 3x , given (0, ), and (-2, ).
Rudiy27

Answer:

We conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.

Step-by-step explanation:

Given the expression

y = 2x² + 3x

Substituting x = 0

y = 2(0)² + 3(0)

y = 0+0

y = 0

  • so when x = 0, y = 0

Thus, the ordered pair is: (0, 0)

Now, substituting x = -2

y = 2x² + 3x

y = 2(-2)² + 3(-2)

y = 8 - 6

y = 2

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Thus, the ordered pair is: (-2, 2)

Therefore, we conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.

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2 years ago
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Hey there,

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<span>In a triangle the sum of two sides is always greater than the third side.

</span><span>A:12,9,21
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7 0
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