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alekssr [168]
3 years ago
15

Solve 6.1−0.3≥c+1. please help me

Mathematics
2 answers:
horsena [70]3 years ago
8 0

Answer:

c≤  24/25

​

Step-by-step explanation:

"0.3" was replaced by "(3/10)". 2 more similar replacement(s). Simplify 3/10

    61     3      

 (—— -  ——) -  (c + 1)  ≥ 0    then simplify 61/10

  10    10    

3.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

    61 - (3)                   29

————————  =  ——

     10                          5

29    

 —— -  (c + 1)  ≥ 0  

 5    

4.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  5  as the denominator :

            c + 1     (c + 1) • 5

   c + 1 =  —————  =  ———————————

              1            5      

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Rewrite the whole as a fraction using  5  as the denominator :

                         c + 1     (c + 1) • 5

   c + 1 =  —————  =  ———————————

                             1            5    

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

                              29 - ((c+1) • 5)     24 - 5c

————————————————  =  ———————

                                          5                5

    24 - 5c

 ———————  ≥ 0  

      5    

 

Multiply both sides by  5  

5.2    Multiply both sides by (-1)

Flip the inequality sign since you are multiplying by a negative number

     5c-24  ≤ 0

5.3    Divide both sides by  5  

     c-(24/5)  ≤ 0

5.4      Add  24/5  to both sides

            c ≤ 24/5

pav-90 [236]3 years ago
3 0

Answer:

wehj

Step-by-step explanation:

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Answer:

D. f(-3) = 11

Step-by-step explanation:

When f(x) is divided by x+3, you get a quotient g(x) and a remainder of 11:

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Multiply both sides by x+3:

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Therefore volume of sphere when we use 3.14 in place of \pi is 35.98cm^3

And the Hal likely error is he uses \pi directly for calculation of volume.

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