What property is y(x+5)

Ed decided to build a storage box. At first, he was planning to build a cubical box with edges of length n inches. To increase t

Mandarinka [93]

Answer:

The new volume is 3n^2+2n inches greater.

Step-by-step explanation:

Volume of a cube = s^3 where s is side of cube

Original volume = n^3

Volume of a Rectangular Prism = LBH

New Volume = (n+1)(n+2)(n)= n^3+3n^2+2n

DIfference = New- original = 3n^2+2n

4 0

3 years ago

How many liters of water must be added to 15 liters of 40 % sugar syrup to obtain 30 % sugar syrup?

Ivanshal [37]

Answer:

The amount of water need to be added is 5 liters.

Step-by-step explanation:

Let's "x" be amount of water in (liters) added to 15 liters of 40% of sugar syrup.

Now find the amount of sugar syrup = 40% of 15

= 0.4 × 15

The amount of sugar syrup = 6 Liters

To dilute 30% we need to find amount of water to be added.

So,

30% of (15 + x) = 6

0.3 × (15 + x) = 6

4.5 + 0.3x = 6

0.3x = 6 - 4.5

0.3x = 1.5

Dividing both sides, by 0.3, we get

x = 5

So, the amount of water need to be added is 5 liters.

6 0

3 years ago

Read 2 more answers

What is 72871872672638+8298197891718989+89792797970120=

serg [7]

Answer:

A 8.469862e+15 so that is the answer hope u get the answer cprrect

7 0

3 years ago

what is the simple formula corresponding to the explicit formula if the first term of the sequence is -10 and the difference bet

mote1985 [20]

Look in the file below

8 0

3 years ago

Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili

lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

B = bugs are present in a computer program.

D = a de-bugging program detects the bug.

The information provided is:

$P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02$

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event E given that another event X has already occurred is:

$P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}$

Use the Bayes' theorem to compute the value of P (B | D) as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333$

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

$=0.3333\times 0.3333\\=0.11108889\\\approx 0.1111$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

$=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0

3 years ago