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3 years ago

Hhhhhhhhhhhhhhhheeeeeeeeeeeeeeeeeelllllllllllllllpppppppppppppppp

Mathematics

2 answers:

OLga [1]3 years ago

6 0

Answer:

Step-by-step explanation:

Pavlova-9 [17]3 years ago

3 0

They have 23 quarters in the piggy bank at most.

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Suppose the solutions of a homogeneous system of four linear equations in five unknowns are all multiples of one nonzero solutio

Akimi4 [234]

Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.

Yes, it's miles true.

Consider the machine as Ax = 0. in which A is 4x5 matrix.

From given dim Nul A=1. Since, the rank theorem states that

The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation

rank A+ dim NulA = n

dim NulA =n- rank A

Rank A = 5 - dim Nul A

Rank A = 4

Thus, the measurement of dim Col A = rank A = five

And since Col A is a subspace of R^4, Col A = R^4.

So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.

8 0

3 years ago

X squared plus y plus 3 equals 7

3241004551 [841]

X2 + y + 3 = 7
×2 + y = 4

7 0

3 years ago

What is the slope of the line that passes through 2,-1 and 2,-5

Eddi Din [679]

Answer:

Undefined.

Step-by-step explanation:

When using the formula y2-y1/x2-x1, the result comes out as -4/0. Any number over a 0 is undefined.

3 0

3 years ago

Last one for like ever

g100num [7]

Answer:

DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Over the last three evenings, Yoko received a total of 73 phone calls at the call center. The third evening, she received 3 time

stealth61 [152]

The first evening she received x calls.
The second evening she received 7 fewer calls than the first evening, so she received x-7 calls.
The third evening she received 3 times as many calls as the first evening, so she received 3x calls.
Over the three evenings she received 73 calls altogether.

$x+x-7+3x=73 \\
5x-7=73 \\
5x=73+7 \\
5x=80 \\
x=\frac{80}{5} \\
x=16 \Leftarrow \hbox{the first evening} \\ \\ \hbox{the second evening:} \\
x-7=16-7=9 \\ \\ \hbox{the third evening:} \\
3x=3 \times 16=48$

The first evening she received 16 calls, the second evening she received 9 calls, the third evening she received 48 calls.

3 0

3 years ago