All categories

3 years ago

PLEASE HELP

Chemistry

1 answer:

Nimfa-mama [501]3 years ago

3 0

Answer:

0.5m/s²

Explanation:

Given parameters:

Mass to be pushed = 300kg

Force = 150N

Unknown:

Acceleration = ?

Solution:

To solve this problem, we need to apply newtons second law of motion which is expressed below:

F = m a

F is the force

m is the mass

a is the acceleration

150 = 300 x a

a = 0.5m/s²

You might be interested in

How are atoms considered the “alphabet” in language of molecules?

luda_lava [24]

Atoms are like the letters of the alphabet the compounds they make are like words.

3 0

3 years ago

QUESTION 3

ohaa [14]

The result would be: loss of farmland

5 0

3 years ago

The liquid that condenses during distillation is called?

AVprozaik [17]

Answer:

the answer is distillate

3 0

3 years ago

A canister of acetylene has a volume of 42 l the temperature of the acetylene is 305 k and the pressure is 780 torr determined t

salantis [7]

PV = nRT

1.026atm * 42l = n * 0.0821L atm/mol K * 305K

n=1.72.

1.72 molecules.

4 0

3 years ago

To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o

Romashka-Z-Leto [24]

Answer:

a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

$\pi r^{2}h$ ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

$r=\frac{d}{2}$

$=\frac{3.36x10^{2}}{2}$

= 168 m

Volume =

$=\frac{22\times 168^{2}\times 21.80}{7}$

$=1.93\times 10^{6} m^{3}$

2.Convert ppm to g/m3 and Solve for mass of F-

$1ppm = 1g/m^{3}$

$0.9ppm = 0.9g/m^{3}$

Because both ppm and g/m3 are same quantity .

$g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}$

$0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}$

$mass\ of\ F- =1.740g$

mass of F- required = 1.740 g

3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

$2Na+F_{2}\rightarrow 2NaF$

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

$\frac {84}{38}\times 1.74$

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

3 0

3 years ago