Answer:
Step-by-step explanation:
9
1. ∠ACB ≅∠ECD ; vertical angles are congruent (A)
2. C is midpoint of AE ; given
3. AC ≅CE; midpoint divides the line segment in 2 congruent segments (S)
4.AB║DE; given
5. ∠A≅∠E; alternate interior angles are congruent (A)
6. ΔABC≅ΔEDC; Angle-Side-Angle congruency theorem
10
1. YX≅ZX; given (S)
2. WX bisects ∠YXZ; given
3. ∠YXW≅∠ZXW; definition of angle bisectors (A)
4. WX ≅WX; reflexive propriety(S)
5. ΔWYX≅ΔWZX; Side-Angle-Side theorem
Only three rectangles are needed, the one at the bottom and the two at the sides.
I hope this helps.
YOU'RE WELCOME :D
Answer:
the answer to this question is equal to 162
Answer:
Step-by-step explanation:
I think the only way you can solve this is to assume that <R means PRT in the given ratio. If I am wrong, I don't think the problem can be solved.
Find <T
Let <T = x
and <PRT = 3x
KLMN is a Parallelagram and therefore two adjacent angles are supplementary.
<PRT + <T = 180 degress
3x + x = 180 degrees
4x = 180
x = 45
So <T = 45
<PRT = 3*45 = 135
If RD is perpendicular to PS then <PDR = 90o
Here's the trick.
RD is also Perpendicular to RT
<MRD + <MRT = 90
<MRT = 180 - 90 - <T
<MRT = 180 - 90 - 45
<MRT = 45
Here comes your answer
=================
<MRD + MRT = 90
<MRD + 45 = 90
<MRD = 45
====================
Note: you must ignore everything to do with the diagram. It is not drawn to scale and the letters are not the same as in the question. The only thing you use is that the figure is a ||gm
