When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. th
RUDIKE [14]
False.
There are 36 possible outcomes, corresponding to numbers 1-6 independently appearing on each of the dice. Only one of those outcomes is double-sixes, resulting in a sum of 12. The probability that the sum is 12 is 1/36.
In short, the 11 outcomes listed in your problem statement are not equally-likely.
10x + 19.95 = 139.95
Subtract 19.95 from both sides
10x =130.00
Divide both sides by 10
X = 13
13 classes
9^3 is in exponential form
