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RSB [31]
3 years ago
11

Help me please..... please

Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0

Answer:

general rule Un=1.8n-21

U100=1.8(100)-21=159

Step-by-step explanation:

a5=a+4d,  a5=-12

a10=a+9d,  a10=-3

-12=a+4d

-3=a+9d subtract the system of equations

-9=-5d solve for d

d=1.8

substitute d into first equation to find a

-12=a+4(1.8)

a=-19.2

un. = a + (n − 1)d

Un=-19.2+(n-1)(1.8)

Un=1.8n-21

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Describe the steps you would take to sketch the graph p(x)=2x^(3)+7x^(2)-3x-18
mojhsa [17]

Answer:

When we have a given function, y = f(x), the general way of graphing the function is finding a lot of coordinate pairs (x, f(x)) and graphing them in a coordinate axis, and then connect them.

So here we have:

p(x) = 2x^(3)+7x^(2)-3x-18

Just let's find the value of p(x) for different values of x, and let's do it.

p(0) = 2*0^(3)+7*0^(2)-3*0-18 = -18

Then the point (0, -18) belongs to the graph

p(1) = 2*1^(3)+7*1^(2)-3*1-18 = 2 + 7 - 3 - 18 = -12

then the point (1, - 12) belongs to the graph.

p(-1) =  2*(-1)^(3)+7*(-1)^(2)-3*(-1)-18  = -2 + 7 + 3 - 18 = -10

then the point (-1, -10) belongs to the graph:

p(2) =  2*2^(3)+7*2^(2)-3*2-18 = 16 + 28 - 6 - 18 =  20

Then the point (2, 20) belongs to the graph

p(-2) =  2*(-2)^(3)+7*(-2)^(2)-3*(-2)-18 = -16 + 28 + 6 - 18 = 0

Then the point (-2, 0) belongs to the graph.

p(-3) =  2*(-3)^(3)+7*(-3)^(2)-3*(-3)-18 = -54 + 63 + 9 - 18 = 0

Then the point (-3, 0) belongs to the graph.

Now that we have 6 points we can graph them and try to connect them.

We also know that this is a cubic polynomial, so we can expect that it changes its direction two times (no more than that) then knowing that we can estimate a shape for the graph, and you will obtain something like the graph of the image below, where I just connected the known points.

6 0
3 years ago
raul bought 2 packs of erasers he found 2 erasers in his backpack now raul has 8 erasers were in each pack?
r-ruslan [8.4K]
There was 3 erasers in each pack because 2 times 3 is 6 plus 2 equals 8. so there are 3 in each pack.
7 0
3 years ago
Read 2 more answers
Help
igomit [66]

3(d + 11) = 6(d + 33)

So you have: 3d + 33 = 6d + 198

which is: -3d = 165

or d = -55

So you have <em>only one answer.</em>

8 0
3 years ago
Read 2 more answers
Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl
lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13

x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88

x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63

x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38

x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13

So, the table becomes:

\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}

Next, calculate the mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}

\bar x = \frac{1845.73}{146}

\bar x = 12.64

Next, the sample variance is:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}

So, we have:

\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}

\sigma^2 = \frac{2393.6875}{145}

\sigma^2 = 16.51

The sample standard deviation is:

\sigma = \sqrt{\sigma^2}

\sigma = \sqrt{16.51}

\sigma = 4.06

6 0
3 years ago
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brilliants [131]
Ok ok fine here is the answer

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