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butalik [34]
3 years ago
8

What is the first quartile in this data set? 67, 68, 69, 70, 70, 70, 72, 73, 73, 75, 75

Mathematics
1 answer:
NARA [144]3 years ago
4 0

<em> </em><em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>✌</em><em>✌</em><em>✌</em>

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Joel is constructing a line perpendicular . He has already constructed three arcs as shown. Use the image to answer the question
IgorC [24]
<span>It must be the same as it was when constructing the arc above P.</span>
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3 years ago
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The object below was made by placing a cone on top of a cylinder. The base of the cone is congruent to the base of the cylinder.
Ber [7]

Answer:

Part 1) The volume of the object is 32\pi\ cm^{3}  or 100.48\ cm^{3}

Part 2) see the procedure

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1)  What is the volume, in cubic centimeters, of the object?

we know that

The volume of the object is equal to the volume of the cylinder plus the volume of the cone

Find the volume of the cone

The volume of the cone is equal to

V=\frac{1}{3}\pi r^{2} h

we have

r=4/2=2\ cm -----> the radius is half the diameter

h=3\ cm

substitute the values

V=\frac{1}{3}\pi (2^{2})(3)=4\pi\ cm^{3}

Find the volume of the cylinder

The volume of the cylinder is equal to

V=\pi r^{2} h

we have

r=4/2=2\ cm -----> the radius is half the diameter

h=(10-3)=7\ cm

substitute the values

V=\pi (2^{2})(7)=28\pi\ cm^{3}

Part 2) Then explain how you found the volume of the total shape

The volume of the total shape is equal to the volume of the cylinder plus the volume of the cone

4\pi\ cm^{3}+28\pi\ cm^{3}=32\pi\ cm^{3} ------> exact value

Find the approximate value of the volume

assume

\pi=3.14

32(3.14)=100.48\ cm^{3}

7 0
3 years ago
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The speed of a boat in still water is 40 mph. If it takes the same time for the boat to travel 8 miles upstream as it does to tr
antoniya [11.8K]

Answer:

Current speed is 40mph

Step-by-step explanation:

We firstly need to know what is intended by upstream and downstream. When the boat travels in the direction of the current (horizontal movement of the water), we say it is moving downstream otherwise it is moving upstream.

Let's assume the speed of the boat is A and that of the current is B, then the speed when it moves dowstream would be A + B and the speed if it moves upstream would be A – B.

In this question, we know that the speed of the boat is 40mph. Given that it takes the same time to travel 8miles upstream as it does to travel 24miles downstream, we have

Speed upstream = 8/t

Speed downstream = 24/t

Respectively.

Let speed of current be X, then

Speed downstream = 40 + X

Speed upstream = 40 – X

From the question we have:

(40 + x)/24 = (40 – X)/8

(40 + x)/3 = (40 – x)/1

3(40 – x) = 40 + X

120 – 3x = 40 – X

120 – 40 = 3x – X

2x = 80

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Therefore, current speed is 40mph

5 0
3 years ago
De║bc, ad=2cm and bd=3cm, then area(Δabc):area(Δade) is equal to
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Answer:

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Step-by-step explanation:

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2 years ago
Tyler is offered to choose between three boxes that look identical. The first box contains 1 red pills and 19 blue pills, the se
Dafna1 [17]

Answer:

A) 0.15

B) 0.36

Step-by-step explanation:

First Box consist 1 red pills and 19 blue pills

second box consist 6 red pills and 14 blue pills

Third box consist 2 red pills and 18 blue pills

a) Prob ( randomly chosen pill is red) = \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}

\frac{1}{60} (1+6+2) = 0.15

b)Prob ( 1 reds and 10 blue pilss) =\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}

= \frac{1}{3} 1.106 = 0.368

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3 years ago
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