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salantis [7]
3 years ago
7

Please help! Simply the polonomials! ​

Mathematics
1 answer:
enot [183]3 years ago
7 0

Answer:

1) 11x^3 - 6x - 3

2) 3x^3 + 4x^2 - 2x - 1

3) 9x^2 - 4

4) -4x^4 + 2x^3 - x^2

5) x^3 - 38x - 12

Step-by-step explanation:

1) (3x^4 + 5x^3 - 7x + 2) - (3x^4 - 6x^3 - x + 5)

Step 1: 3x^4 + 5x^3 - 7x + 2 - 3x^4 + 6x^3 + x - 5 (multiply the terms in the parenthesis by the constants, which are 1 and -1)

Step 2: 3x^4 - 3x^4 + 5x^3 + 6x^3 - 7x + x + 2 - 5 (reorganize the polynomial by exponential values (ex: x^4 before x^3 before x^1))

Step 3: <u>11x^3 - 6x - 3</u> (add like terms)

2) (3x^3 + 8x - 3) + (4x^2 - 10x + 2)

Step 1: 3x^3 + 8x - 3 + 4x^2 - 10x + 2 (multiply the terms in the parenthesis by the constants)

Step 2: 3x^3 + 4x^2 + 8x - 10x - 3 + 2 (reorganize the polynomial)

Step 3: <u>3x^3 + 4x^2 - 2x - 1</u> (add like terms)

3) (3x + 2)(3x - 2)

Step 1: 9x^2 - 6x + 6x - 4 (Use FOIL to multiply binomials, or multiply the first terms, outside terms, inside terms, then last terms)

Step 2: <u>9x^2 - 4</u> (add like terms)

4) -x^2(4x^2 - 2x + 1)

Step 1: (-x^2*4x^2) + (-x^2*(-2x)) + (-x^2*1) (multiply -x^2 by each term)

Step 2: <u>-4x^4 + 2x^3 - x^2</u> (simplify; remember x^2 is the same as -1*x^2)

5) (x + 6)(x^2 - 6x - 2)

Step 1: ((x*x^2) + (x*(-6x)) + (x*(-2))) + ((6*x^2) + (6*(-6x)) + (6*(-2))) (multiply the first term in the binomial by each term in the trinomial, and do the same with the second term)

Step 2: x^3 - 6x^2 + 6x^2 - 2x - 36x - 12 (simplify and reorganize)

Step 3: <u>x^3 - 38x - 12</u> (add like terms again)

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Answer:

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Step-by-step explanation:

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4 years ago
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-10 - | 5 -12 | + 3 + | 5 + 12 | =
Vladimir79 [104]

Answer:

3

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| - a | = | a | = a

given

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5 0
2 years ago
y = –6x 2 –12x – 2y = –4 how many solutions does this linear system have? one solution: (0, 0) one solution: (1, –4) no solution
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Y = -6x + 2 . . . . . . . . (1)
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5 0
3 years ago
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