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Nataly [62]
2 years ago
6

-10 - | 5 -12 | + 3 + | 5 + 12 | =

Mathematics
1 answer:
Vladimir79 [104]2 years ago
5 0

Answer:

3

Step-by-step explanation:

the absolute value function always returns a positive value , that is

| - a | = | a | = a

given

- 10 - | 5 - 12 | + 3 + | 5 + 12 |

= - 10 - | - 7 | + 3 + | 17 |

= - 10 - 7 + 3 + 17

= 3

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What is the perimeter of the figure to the nearest tenth of a millimeter?
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C because first you would find the circumference of the circle which is pi times diameter, which is 18.84 but since it is a semi-circle you would divide by 2 which is 9.42. Then you do 3+3=6 + the length which is 6 so you get 12. 12+9.42=21.42 and if you round that to the nearest tenth it is 21.42.
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4 years ago
A survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the resul
pav-90 [236]

Answer:

95% confidence interval for the proportion of the adults who were opposed to the death penalty is (0.668, 0.704).

Step-by-step explanation:

We are given that a survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the results below, where X refers to the number of the respondents who were in favor.

X = 1,790

N = 2,610

\hat p = Sample proportion = X/N = 0.6858

Firstly, the pivotal quantity for 95% confidence interval for the population proportion  is given by;

     P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.6858

           n = sample of respondents = 2,610

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at

                                   2.5% level of significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }]

  = [ 0.6858-1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} } , 0.6858+1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} } ]

  = [0.668 , 0.704]

Therefore, 95% confidence interval for the population proportion of the adults is (0.668, 0.704).

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Answer:

Step-by-step explanation:

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