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Thepotemich [5.8K]
3 years ago
15

y = –6x 2 –12x – 2y = –4 how many solutions does this linear system have? one solution: (0, 0) one solution: (1, –4) no solution

infinite number of solutions
Mathematics
2 answers:
Ksju [112]3 years ago
6 0

Answer:

infinite number of solutions



lara [203]3 years ago
5 0
Y = -6x + 2 . . . . . . . . (1)
-12x - 2y = -4 . . . . . . (2)
Putting (1) into (2), we have
-12x - 2(-6x + 2) = -4
-12x + 12x - 4 = -4
-4 = -4

Therefore, the system has infinite number of solutions.
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Events A and B satisfy the conditions shown P (A)=0.3 P (B)=0.1 P (A and B)=0.03 What statement about the two events must be tru
Sliva [168]

Answer:

D

Step-by-step explanation:

P(A)=0.3

P(B)=0.1

P(A)×P(B)=0.3×0.1=0.03

P(A and B)=P(A)×P(B)

They are independent.

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3 years ago
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Writing to explain what are compatible numbers? What compatible numbers would you pick to estimate the diferrent of 777-248? Why
Sphinxa [80]
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8 0
3 years ago
0.00000003 in scientific notation
tester [92]

Answer:

3×10x^{-8}

Step-by-step explanation:

0.00000003

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the  

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6 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
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