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Thepotemich [5.8K]
3 years ago
15

y = –6x 2 –12x – 2y = –4 how many solutions does this linear system have? one solution: (0, 0) one solution: (1, –4) no solution

infinite number of solutions
Mathematics
2 answers:
Ksju [112]3 years ago
6 0

Answer:

infinite number of solutions



lara [203]3 years ago
5 0
Y = -6x + 2 . . . . . . . . (1)
-12x - 2y = -4 . . . . . . (2)
Putting (1) into (2), we have
-12x - 2(-6x + 2) = -4
-12x + 12x - 4 = -4
-4 = -4

Therefore, the system has infinite number of solutions.
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I need major help!!!!
Mama L [17]
1) Area of a circle = πr^2
Radius = 13.2 ÷ 2
= 6.6
Area = (3.14)(6.6)^2
= 136.78cm^2

I hope this helps!
6 0
3 years ago
In the diagram below, ST is parallel to QR. angle P is 40 degrees, and QST is 2R+8. Find the measure of STR in degrees.
lozanna [386]

Answer:

148º

Step-by-step explanation:

Use the information given:

  • The measure of a straight line is 180º. So angle PST=180-(2R+8)
  • Since ST and QR are parallel, angle PST=angle PQR. Now, angle PQR=180-(2R+8)
  • The sum of a triangle's interior angles is 180º. So 40+180-2R-8+R=180º.
  • Combine like terms, 212-R=180
  • Subtract, -R=-32
  • Convert to positive, R=32º

With R=32º, we can find angle QST and PQR. Angle QST=2(32)+8=64+8=72º. So angle PQR=180º-72º=108º. The sum of a quadrilateral's interior angles is 360º:

  • 32º+72º+108º+STR=360º
  • Combine like terms, 212º+STR=360º
  • Subtract, STR=148º
3 0
3 years ago
Two identical quarter circles are cut from a rectangle as shown
ArbitrLikvidat [17]

Answer:

The quarter circle Is connect the triangle

it is Cut.

Step-by-step explanation:

Ihope makatulong

Pa follow

5 0
2 years ago
The ratio of the numerator to the denominator of a fraction is 2 to 3. If both the numerator and the denominator are increased b
masha68 [24]

Answer:

The fraction is \frac{4}{6}

Option (B) is correct.

3n-2d=0  and 4n+8=3d+6

Step-by-step explanation:

Let n denotes numerator and d denotes denominator of the fraction.

Given : The ratio of the numerator to the denominator of a fraction is 2 to 3.

That is \frac{n}{d}=\frac{2}{3}

Cross multiply , we get,

3n=2d

Or, 3n-2d=0   ........(1)

Also, given : . If both the numerator and the denominator are increased by 2, the fraction becomes 3/4

That is \frac{n+2}{d+2}=\frac{3}{4}

Cross multiply , We get,

4{n+2}={3}{d+2}

4n+8=3d+6  .........(2)

3d-4n=2  .......(3)

Thus, from (1) and (2) , option (B) follows.

Solving equation (1) and (3) to get the original fraction using elimination method,

3n - 2d = 0    ............(1)

and 3d - 4n = 2       .........(3)

Multiply equation (1) by 3 , we get ,

9n - 6d = 0  ..........(4)

Multiply equation (3) by 2 , we get ,

-8n + 6d = 4 ..........(5)

Adding (4) and  (5) , we get,

9n - 6d -8n + 6d = 4 + 0

⇒ n = 4

Put n = 4 in (1), we get

3n - 2d = 0 ⇒ 3(4) - 2d = 0 ⇒ 12 -2d = 0  ⇒  12 = 2d ⇒ d = 6

so, the numerator is 4 and  the denominator is 6.

Thus, the fraction is \frac{4}{6}


6 0
2 years ago
Find the standard form of the equation of the parabola with a focus at (5, 0) and a directrix at x = -5.
Elena-2011 [213]
Let's notice, the focus is at (5,0) and the directrix at x = -5.

keep in mind that there's a distance "p" from the vertex to either of those fellows, therefore, if the focus is at 5,0 and the directrix x = -5, the vertex is half-way between them, check the picture below.

notice the distance "p" there, now, is a horizontal parabola, opening to the right, meaning the value for "p" is positive, or just 5, thus

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})}
\\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}})
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=0\\
k=0\\
p=5
\end{cases}\implies (y-0)^2=4(5)(x-0)\implies y^2=20x
\\\\\\
\cfrac{y^2}{20}=x\implies \cfrac{1}{20}y^2=x

8 0
3 years ago
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