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kobusy [5.1K]
3 years ago
5

Is -3.8 bigger less than or equal to -4 1 / 2

Mathematics
2 answers:
irga5000 [103]3 years ago
8 0

Answer:

bigger

Step-by-step explanation:

Katena32 [7]3 years ago
7 0

Answer:

Bigger

Step-by-step explanation:

-3.8 is bigger because negative numbers closer to 0 are actually bigger than negative numbers farther away.

If -4\frac{1}{2} is broken down into simpler form it becomes -9/2 which reduces to -4.5 in decimal form. -4.5 is farther away from 0 on a number line thus it is smaller. Thus -3.8 > -4.5

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Which expression has the same value as <br> 5<br> +<br> (<br> −<br> 4<br> )<br> 5+(−4)?
stellarik [79]

Answer: 5+-20-4 or -24+5 or -15-4

Step-by-step explanation: (5)+(−4)(5)+(−4) 5+-20-4 -24+5 or -15-4 -19

6 0
2 years ago
A cone shaped building has a height of 11.4 meters and a base with a diameter of 12 meters . The building will be filled with ro
Vlad1618 [11]

Answer:

The answer to your question is  $ 8591.04

Step-by-step explanation:

Data

height = 11.4 m

diameter = 12 m

cost = $20/ft³

Process

1.- Calculate the volume of the cone

Formula

Volume = 1/3 πr²h

Substitution

Volume = 1/3 (3.14)(12/2)²(11.4)

Simplification

Volume = 1/3(1288.66)

Volume = 429.55 m³

2.- Calculate the cost

                $20 ----------------- 1 m³

                   x   ----------------- 429.55 m³

                   x = (429.55 x 20)/ 1

                   x = $ 8591.04

8 0
3 years ago
What properties would you use to solve x/3=12 (multiple choice)
butalik [34]
C

explanation : the equation is division and since you don’t know what the variable x is, you multiply 3 and 12 to find x
5 0
3 years ago
Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.
Kobotan [32]

Answer:

t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457

p_v =P(t_{75}  

Comparing the p value with a significance level for example \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.  

Step-by-step explanation:

Data given and notation

\bar X_{A}=3.7 represent the mean for athletes  

\bar X_{NA}=4.1 represent the mean for non athletes  

s_{A}=1.1 represent the sample standard deviation for athletes  

s_{NA}=1.3 represent the sample standard deviation for non athletes

n_{A}=32 sample size for the group 2  

n_{NA}=45 sample size for the group 2  

\alpha=0.01 Significance level provided  

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of  hypothesis would be:  

Null hypothesis:\mu_{A}-\mu_{NA}\geq 0  

Alternative hypothesis:\mu_{A} - \mu_{NA}< 0  

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}} (1)  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457

P value  

We need to find first the degrees of freedom given by:

df=n_A +n_{NA}-2=32+45-2=75

Since is a one left tailed test the p value would be:  

p_v =P(t_{75}  

Comparing the p value with a significance level for example \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.  

5 0
3 years ago
20 POINTS PLZ HELP
blondinia [14]

Answer:

It would be a straight line.

Step-by-step explanation:

It would be a negative, linear line. It would be steep.

3 0
3 years ago
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