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3 years ago

WILL GIVE BRAINLIEST!!!!!!

Mathematics

1 answer:

Mumz [18]3 years ago

8 0

Answer: 126 milligrams

Step-by-step Easy to answer but all your doing is converting your mg's and 35% into decimals. and you will get your answer

You might be interested in

Determine the values of the constants r and s such that i(x, y) = x rys is an integrating factor for the given differential equa

garri49 [273]

$\underbrace{y(7xy^2+6)}_{M(x,y)}\,\mathrm dx+\underbrace{x(xy^2-1)}_{N(x,y)}\,\mathrm dy=0$

For the ODE to be exact, we require that $M_y=N_x$ , which we'll verify is not the case here.

$M_y=21xy^2+6$
$N_x=2xy^2-1$

So we distribute an integrating factor $i(x,y)$ across both sides of the ODE to get

$iM\,\mathrm dx+iN\,\mathrm dy=0$

Now for the ODE to be exact, we require $(iM)_y=(iN)_x$ , which in turn means

$i_yM+iM_y=i_xN+iN_x\implies i(M_y-N_x)=i_xN-i_yM$

Suppose $i(x,y)=x^ry^s$ . Then substituting everything into the PDE above, we have

$x^ry^s(19xy^2+7)=rx^{r-1}y^s(x^2y^2-x)-sx^ry^{s-1}(7xy^3+6y)$
$19x^{r+1}y^{s+2}+7x^ry^s=rx^{r+1}y^{s+2}-rx^ry^s-7sx^{r+1}y^{s+2}-6sx^ry^s$
$19x^{r+1}y^{s+2}+7x^ry^s=(r-7s)x^{r+1}y^{s+2}-(r+6s)x^ry^s$
$\implies\begin{cases}r-7s=19\\r+6s=-7\end{cases}\implies r=5,s=-2$

so that our integrating factor is $i(x,y)=x^5y^{-2}$ . Our ODE is now

$(7x^6y+6x^5y^{-1})\,\mathrm dx+(x^7-x^6y^{-2})\,\mathrm dy=0$

Renaming $M(x,y)$ and $N(x,y)$ to our current coefficients, we end up with partial derivatives

$M_y=7x^6-6x^5y^{-2}$
$N_x=7x^6-6x^5y^{-2}$

as desired, so our new ODE is indeed exact.

Next, we're looking for a solution of the form $\Psi(x,y)=C$ . By the chain rule, we have

$\Psi_x=7x^6y+6x^5y^{-1}\implies\Psi=x^7y+x^6y^{-1}+f(y)$

Differentiating with respect to $y$ yields

$\Psi_y=x^7-x^6y^{-2}=x^7-x^6y^{-2}+\dfrac{\mathrm df}{\mathrm dy}$
$\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C$

Thus the solution to the ODE is

$\Psi(x,y)=x^7y+x^6y^{-1}=C$

4 0

3 years ago

You need to find three numbers that come in quick succession in the order of numbers (ex. 1, 2 and 3) and which

eimsori [14]

Answer:

set middle number=x

then left side number=x-1

and right side number=x+1

(x-1)+x+(x+1)＝30

3x=30

x=10

x-1=9

x+1=11

numbers are 9,10,11

4 0

3 years ago

Please help, I’ll mark you as brainliest!!!!!

kolezko [41]

Answer:10

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The tread on a given tire wears at a consistent rate based on the number of rotations the tire makes.

aksik [14]

I think it is 3200 because you divide 8000 by 5 then multiply that by 2

4 0

3 years ago

The mean IQ score of students in a particular calculus class is 110, with a standard deviation of 5. Use the Empirical Rule to f

Anika [276]

Answer:

2.5%

Step-by-step explanation:

If the data set has a bell-shaped distribution, then you can use 68-95-99.7, or Empirical, rule. With bell-shaped distributions, 68% of results lie within 1 standard deviation of the mean, 95% of results lie within 2 standard deviations, and 99.7% lie within 3 standard deviations.

Your mean is 110, and you have a standard deviation of 5. This means that 68% of all students fall between IQ scores of 105 (110 - 5) and 115 (110 + 5), one standard deviation from the mean. To get 95% of the students, you need to go one more standard deviation out, so then you have 100 (105 - 5) and 120 (115 + 5), two standard deviations from the mean. 99.7% of the students fall between 95 (100 - 5) and 125 (120 + 5). What you want is to find the percentage of students with an IQ above 120.

The way I'd handle this is starting with what I know is absolutely, without a doubt, below 120. If you drew a quick bell curve to represent this data, everything to the left of the mean, 110, could be counted out right away (I usually color in half of the bell curve because I like the visual representation). Just like that, 50% of your data is gone. From there, I know 120 is right at 2 standard deviations away, so I color in all the way up to the 95% mark, but remember that when we took away 50%, you don't want to count all the standard deviations on the left side of the bell curve twice. So instead, take the 95% and cut it in half, which is 47.5%. Alternatively, you can start at 50% and count up 1 standard deviation (34%), and up one more (13.5%) and get the same result, 47.5%. So now you know 50 + 47.5 = 97.5% of results are LOWER than 120. To figure out what's higher than 120, all you have to do is see that

100% - 50% - 47.5% = 2.5%

And then you can see that 2.5% of students have an IQ over 120.

5 0

3 years ago