NEED HELP ASAP!! PLEASE SHOW AND EXPLAIN YOUR ANSWER!
1 answer:
A. The decrease in Car 1 value is constant at 6000 from year to year. Its value can be described by a linear function.
The decrease in Car 2 value is a constant percentage of its current value from year to year. Its value can be described by an exponential function.
B. The slope of the Car 1 function is -6000, and the value is 32000 in year 1, so the value function for Car 1 can be written as
... f(x) = 32000 -6000(x-1)
... f(x) = 38000 -6000x
The value multiplier for Car 2 from year to year is 27455/32300 = 0.85, so the value function for Car 2 can be written as
... f(x) = 32,300·0.85^(x-1)
... f(x) = 38000·0.85^x
C. There is a significant difference in value after 5 years. Car 2 is worth more than double the value of Car 1 in year 5. That year, their values are ...
... car 1: $8000
... car 2: $16861
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Turn both equations into slope-intercept form [ y = mx + b ].
x + 3y = 3
~Subtract x to both sides
3y = 3 - x
~Divide 3 to everything
y = 1 - x/3
~Reorder
y = -1/3x + 1
4x + 3y = -6
~Subtract 4x to both sides
3y = -6 - 4x
~Divide 3 to everything
y = -2 - 4x/3
~Reorder
y = -4/3x - 2
Graph of the equations will be shown below. Note that the solution of graphing two equations will be where both equations intersect. Both lines intersect at (-3, 2), hence making that the solution.
Best of Luck!
