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CaHeK987 [17]
3 years ago
12

NEED HELP ASAP!! PLEASE SHOW AND EXPLAIN YOUR ANSWER!

Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0

A. The decrease in Car 1 value is constant at 6000 from year to year. Its value can be described by a linear function.


The decrease in Car 2 value is a constant percentage of its current value from year to year. Its value can be described by an exponential function.


B. The slope of the Car 1 function is -6000, and the value is 32000 in year 1, so the value function for Car 1 can be written as

... f(x) = 32000 -6000(x-1)

... f(x) = 38000 -6000x


The value multiplier for Car 2 from year to year is 27455/32300 = 0.85, so the value function for Car 2 can be written as

... f(x) = 32,300·0.85^(x-1)

... f(x) = 38000·0.85^x


C. There is a significant difference in value after 5 years. Car 2 is worth more than double the value of Car 1 in year 5. That year, their values are ...

... car 1: $8000

... car 2: $16861

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Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Ksenya-84 [330]

<u>Part a)</u> Use a system of inequalities to model the scenario

Let

x-------> represent babysitting hours

y-------> represent tutoring hours  

we know that

x+y \leq20 --------> inequality 1  

6x+10y \geq 75 --------> inequality 2

<u>Part b)</u> Use the model created in part A to create a graph representing Jeanne’s probable income earned and possible number of hours worked this week

we know that

x+y \leq20 --------> inequality 1

This inequality represent Jeanne’s possible number of hours worked this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 1

6x+10y \geq 75 --------> inequality 2  

This inequality represent Jeanne’s probable income earned this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 2

<u>Part c)</u> Analyze the set of coordinate values that represent solutions for the model created in part A. Choose one of the coordinates within the solution and algebraically prove that the coordinate represents a true solution for the model

we have the system of inequalities

x+y \leq20 --------> inequality 1

6x+10y \geq 75 --------> inequality 2

the solution of the system of inequalities is the shaded area

using a graph tool

see the attached figure N  3

Let

A(10,10) ------> see the attached figure N  3

The point belongs to the shaded area, so it is a system solution.

If the point is a solution, it must satisfy both inequalities.

<u>Prove algebraically </u>

A(10,10)

substitute the value of x and y in the inequalities

<u>inequality 1</u>

10+10 \leq20

20 \leq20 ------> is ok

<u>inequality 2</u>

6*10+10*10 \geq 75

160 \geq 75 -------> is ok

the point A satisfy both inequalities

therefore

the point A is a solution of the system

7 0
3 years ago
Rewrite the following polynomial in standard form.<br> 1 + 10x3 + x2
boyakko [2]

Answer:

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Step-by-step explanation:

1) 1 + 10 × 3 + x

2) 1 + 30 + x

3) 31 + x

4 0
2 years ago
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all you have to do is see whether both variables of each point meet both contraints:

for a) 1<3 and 2>1 is true so a is a solution to the system

5 0
3 years ago
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user100 [1]

Step-by-step explanation:

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= 2( 4m-1+3m+2)

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8 0
2 years ago
Find the values of x and y
Readme [11.4K]

y=5

x=30

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