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zheka24 [161]
3 years ago
10

The dot plot shows the number of chess games won by each of the 20 students in a competition.

Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0

Answer:

Letter B is the correct answer. Median is 4 and IQR is 5.

Step-by-step explanation:

son4ous [18]3 years ago
5 0

Jason : 8,8,11,13,14,14,15,18,21,22,22,27,27,28,30

           median = 18

           IQR = 27 - 13 = 14

Ed : 7,12,12,15,19,21,21,21,21,22,23,23,26,27,27

       median = 21

       IQR = 23 - 15 = 8

Their medians cannot be compared based on their IQR's are 6 points apart

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If cos(xy) = 3x+1 , find dy/dx
lisabon 2012 [21]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2867070

_______________


          dy
Find  ——  for an implicit function:
          dx

cos(xy) = 3x + 1.


First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

\mathsf{\dfrac{d}{dx}\big[cos(xy)\big]=\dfrac{d}{dx}(3x+1)}\\\\\\
\mathsf{-\,sin(xy)\cdot \dfrac{d}{dx}(xy)=\dfrac{d}{dx}(3x)+\dfrac{d}{dx}(1)}


Apply the product rule to differentiate that term at the left-hand side:

\mathsf{-\,sin(xy)\cdot \left[\dfrac{d}{dx}(x)\cdot y+x\cdot \dfrac{dy}{dx}\right]=3+0}\\\\\\
\mathsf{-\,sin(xy)\cdot \left[1\cdot y+x\cdot \dfrac{dy}{dx}\right]=3}\\\\\\
\mathsf{-\,sin(xy)\cdot \left[y+x\cdot \dfrac{dy}{dx}\right]=3}

   

Now, multiply out the terms to get rid of the brackets at the left-hand
                                       dy
side, and then isolate  —— :
                                       dx

\mathsf{-\,sin(xy)\cdot y-sin(xy)\cdot x\cdot \dfrac{dy}{dx}=3}\\\\\\
\mathsf{-\,y\,sin(xy)-x\,sin(xy)\cdot \dfrac{dy}{dx}=3}\\\\\\
\mathsf{-\;x\,sin(xy)\cdot \dfrac{dy}{dx}=3+y\,sin(xy)}\\\\\\\\
\therefore~~\mathsf{\dfrac{dy}{dx}=\dfrac{3+y\,sin(xy)}{-\;x\,sin(xy)}\qquad\quad for~~x\,sin(xy)\ne 0\qquad\quad\checkmark}


and there it is.


I hope this helps. =)


Tags:  <span><em>implicit function derivative implicit differentiation chain product rule differential integral calculus</em>
</span>
4 0
4 years ago
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