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zheka24 [161]
3 years ago
10

The dot plot shows the number of chess games won by each of the 20 students in a competition.

Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0

Answer:

Letter B is the correct answer. Median is 4 and IQR is 5.

Step-by-step explanation:

son4ous [18]3 years ago
5 0

Jason : 8,8,11,13,14,14,15,18,21,22,22,27,27,28,30

           median = 18

           IQR = 27 - 13 = 14

Ed : 7,12,12,15,19,21,21,21,21,22,23,23,26,27,27

       median = 21

       IQR = 23 - 15 = 8

Their medians cannot be compared based on their IQR's are 6 points apart

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12*3= 36

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I hope this helped you! <3
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The perimeter of a rectangular pentagon is 100 inches. Find the length of each side
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solution:

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3 0
3 years ago
300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a do
katrin2010 [14]

This Question is not complete

Complete Question:

300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a dog, 180 have a cat, and 150 have a cat and a dog. Using this information, answer each of the following questions, Let D be the event that a randomly selected student has a dog and C be the event that a randomly selected student has a cat.

a . What is P(D), the probability that a student in the class has a dog?

b. What is P(C), the probability that a student in the class has a cat?

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

Answer:

a. 2/3

b) 3/5

c) 1/2

d) 19/ 15 = 1 4/15

Step-by-step explanation:

The formula for probability =

Number of possible outcomes ÷ Number of events.

Total number of Students = 300

Number of Students that have a dog = 200

Number of Students that have a cat = 180

Number of Students that have a dog and cat = 150

a. What is P(D), the probability that a student in the class has a dog?

In the question, the given data is interpreted as :

Number of possible outcomes = 200

Number of events = 300

P(D) = 200/300

= 2/3

Therefore, the probability that a student has a dog = 2/3

b. What is P(C), the probability that a student in the class has a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 180

Number of events = 300

P(D) = 180/300

= 3/5

Therefore, the probability that a student has a cat = 3/5

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 150

Number of events = 300

P(D) = 150/300

= 1/2

Therefore, the probability that a student has a dog and cat = 1/2

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

The is calculated as

P(D) + P(C)

In the above question,

P(D) is calculated as 2/3

P(C) is calculated as 3/5

Therfore, P(D or C), the probability that a student in the class has a dog or a cat is calculated as:

= 2/3 +3/5

= 19/15 = 1 4/15

7 0
3 years ago
The total weight of a box cannot exceed 17 pounds so far she has packed 3 1/4 pictures two books weighing 1 3/4 pounds and a jac
tatuchka [14]
You can pack up to 10 1/5 pounds more stuff without going over
8 0
4 years ago
Help me with ths plz <br>a.5<br>b.6<br>c.7<br>d.8
Black_prince [1.1K]
The answer is b.6 hope that helps :)


8 0
4 years ago
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