Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
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Answer:
Step-by-step explanation:
5x3x4=
Answer:
Step-by-step explanation:
36 d²-36 d+9=9(4d²+4d+1)
=9[4d²+2d+2d+1]
=9[2d(2d+1)+1(2d+1)]
=9(2d+1)(2d+1)
=9(2d+1)²
=[3(2d+1)]²
=(6d+6)²
length=6d+6
perimeter=4(6d+6)=24d+24
when d=2
length=6×2+6=18in
perimeter=4×18=72 in
area=18²=324 in²
Answer:
The answer would be 150,000 to 249,999