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3 years ago

Here help please........................

Mathematics

2 answers:

Paraphin [41]3 years ago

6 0

It’s 2 bro try to do it if I’m wrong I’m sorry but it’s 2

AleksandrR [38]3 years ago

3 0

Answer: The value of zero its zero

Step-by-step explanation:

The place value of zero in any number is always zero. Zero may hold any place in a number, but its value will remain to be zero.

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HELP SUPER FAST PLS A rectangular cardboard has dimensions as shown. The length of the cardboard can be found by dividing its ar

Yuki888 [10]

Ok, so area/width=length

then they gave you mixed fractions
they want you to practice converting mixed fractions into improper fractions and dividing them

rmember, improper fractions are a/b where a>b sometimes

and also remember that $\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}$

okie dokie

width
4 and 1/2=width
4+1/2=width
8/2+1/2=width
9/2=width

area=36 and 3/4
area=36+3/4
area=144/4+3/4
area=147/4

so area/width=length
$\frac{\frac{147}{4}}{\frac{9}{2}}=length$
$\frac{(147)(2)}{(4)(9)}=length$
$\frac{294}{36}=length$
$\frac{49}{6}=length$
$\frac{48}{6}+\frac{1}{6}=length$
$8+\frac{1}{6}=length$

so the length is $8 \space\ and \space\ \frac{1}{6} \space\ in$

8 0

3 years ago

In a recent month, 88% of automobile drivers filled their vehicles with regular gasoline, 2% purchased midgrade gas, and 10% bou

Nimfa-mama [501]

Answer:

b) 0.2464

c) 0.0580

d) 0.2952

Step-by-step explanation:

Probability of those that purchased regular gas = 88% = 0.88

2% purchased mid grade gas

10% purchased premium gad

Given that a driver bought regular gas, 28% paid with credit card

Given that a driver bought mid grade gas, 34% paid with credit card

Given that a driver bought premium gas, 42% paid with credit card

Let R represent drivers that bought regular gas

Let M represent drivers that bought mid grade gas

Let P represent drivers that bought premium gas

Let C represent credit card payment

Let NC represent non-credit card payment

Pr(R) = 88% = 0.88

Pr(M) = 2% = 0.02

Pr(P) = 10% = 0.10

Pr(C|R) = 28%= 0.28

Pr(C|M) = 34%= 0.34

Pr(C|P) = 42%= 0.42

Pr(NC|R) = 1 - 0.28= 0.72

Pr(NC|M) = 1 - 0.34 = 0.66

Pr(NC|P) = 1 - 0.42 = 0.58

Using multiplication rule

Pr(AnB) = Pr(A) * Pr(B|A) = Pr(B) * Pr(A|B)

Using conditional probability,

P(B|A) = Pr(AnB) / Pr(A)

Pr(CnR) = Pr(R) * Pr(C|R)

= 0.88*0.28

= 0.2464

Pr(CnM) = Pr(M) * Pr(C|M)

= 0.02*0.34

= 0.0068

Pr(CnP) = Pr(P) * Pr(C|P)

= 0.10*0.42

= 0.0420

b) the probability that an automobile driver filled with regular gasoline AND paid with a credit card =

Pr(CnR)

= 0.2464

c) the probability that an automobile driver filled with premium gasoline AND did NOT pay with a credit card = Pr(P n NC) = Pr(NC|P) * Pr(P)

= 0.58 * 0.10

= 0.0580

d) The probability of those that paid with credit card is given as

Pr(CnR) + Pr(CnM) + Pr(CnP)

= 0.2464 + 0.0068 + 0.042

= 0.2952

7 0

3 years ago

3kg 250g: 5kg pls tell me the answer I have exams

larisa86 [58]

Answer:

Well if it made sense..

Step-by-step explanation:

3 0

3 years ago

What is the area of a sector when r=3/4 and theta=pi/3

spayn [35]

Answer: 73

Step-by-step explanation:

5 0

3 years ago

Can someone help me with this please.

tatuchka [14]

Answer:

x = 29

Step-by-step explanation:

(x + 3) + (x - 1) + (x + 1) = 90

3x + 3 = 90

3x = 87

x = 29

7 0

3 years ago

Read 2 more answers