Answer:
no no no! don't touch me there that is my no no square
Step-by-step explanation:
Given:
The graph of a function is given.
To find:
The range of the graph.
Solution:
We know that, the domain is the set of input values and range is the set of output values.
In a graph, domain is represented by the x-axis and range is represented by the y-axis.
From the given graph it is clear that there is an open circle at (-8,-8) and a closed circle at (3,4). It means the function is not defined at (-8,-8) but defined for (3,4).
The graph of the function is defined over the interval 
. So, the domain is (-8,3].
The values of the function lie in the interval 
. So, the range is (-8,4].
Therefore, the range of the function are all real values over the interval (-8,4].
95.0cm is the answer of this
<h2>
Answer:</h2>
The statement that best describes Imara's error is:
Option: D
D). She did not find the side lengths of the square with an area of 625.
<h2>
Step-by-step explanation:</h2>
Imara correctly did the previous calculation.
i.e. she correctly determined the area of square with side length 20 units (as 400 square units) and 15 units (i.e. 225 square units)
But when she sum the area of two squares then it won't give the length of hypotenuse it would give the area of a square.
Hence, the correct answer is:
Option: D
Answer:
29° ; 61°
Step-by-step explanation:
Let one angle = x°
Other angle = (x + 32)°
x + x + 32 = 90 {given they are complementary}
2x + 32 = 90
2x = 90 -32
2x = 58
x = 58/2
x = 29
One angle = 29°
Other angle = 29 + 32 = 61°
