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GREYUIT [131]
3 years ago
14

You've decided you want to plan for your room. At the gardening store, there are four different kinds of plants (two lip, firm,

cactus, and focus) and 4 different kinds of pots to hold the plants (Clay pot, plastic pot, metal pot, and wood pot).
Mathematics
1 answer:
jeyben [28]3 years ago
7 0
Can you ask the question not just tell the problem
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What is the rate of change ? <br>y=-5x-3​
KatRina [158]

Answer:

the rate of change is -5.

Step-by-step explanation:

y = -5x - 3

-5 = rate of change

-3 = x intercept

6 0
3 years ago
Read 2 more answers
I need to figure what figure A and B is.
Alexeev081 [22]
I can't see the whole graph
3 0
3 years ago
0.3(4+8)/-0.1+5/(9.2+13.2) HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
aleksklad [387]
0.3(4+8)/-0.1+5/(9.2+13.2)= -35.7767857143
8 0
2 years ago
The sum of two numbers is 40 and their difference is 6.5, what is their product? show work please
Finger [1]
Let b>a, 

a+b=40 so we can say a=40-b

We are told that b-a=6.5, using a found above in the equation gives us:

b-(40-b)=6.5

b-40+b=6.5

2b-40=6.5

2b=46.5

b=23.25, and since  a=40-b

a=40-23.25

a=16.75

So a=16.75 and b=23.25

check...

16.75+23.25=40, 40=40

23.25-16.75=6.5, 6.5=6.5

4 0
3 years ago
100 Brainliest up for grabs to person who can answer all of these with no links:
kogti [31]

Using a discrete probability distribution, it is found that:

a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

c) The expected value is of 1.3 lawns mowed on a randomly selected day.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:

  • P(X = 0) = 0.2.
  • P(X = 1) = 0.4.
  • P(X = 2) = 0.3.
  • P(X = 3) = 0.1.

Item a:

P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

Item b:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2 = 0.8

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

Item c:

The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:

E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.

The expected value is of 1.3 lawns mowed on a randomly selected day.

More can be learned about discrete probability distributions at brainly.com/question/24855677

6 0
3 years ago
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