Answer:
p = -1 q = -4
Step-by-step explanation:
a system of eq and solve for p and q ??? can do :)
Eq. 1) 8p + 2q = - 16
Eq. 2) 2p - q = 2
use Eq .2 and solve for q
2p - 2 = q
plug into Eq.1 with q
8p +2(2p - 2) = - 16
8p +4p -4 = -16
12p = - 12
p = -1
plug -1 into Eq. 1 for p and solve for q
8(-1) + 2q = - 16
-8 + 2q = - 16
2q = -8
q = -4
False pls mark meh braliest
Answer:
The period of given function is 
So, Option B is correct.
Step-by-step explanation:
In this question we need to find the period of the function y= 3 sin x/8
The formula used to find period of function is: 
We need to know the value of b.
To find the value of b we compare the standard equation with the equation of function given.
Standard Equation: y = a sin(bx - c) +d
Given Equation: y= 3 sin(x/8)
Comparing we get:
a= 3
b= 1/8
c= 0
d=0
So, we get the value of b i.e 1/8. Putting it in the formula to find period of given function.


Solving,


So, the period of given function is 
C.(-1,3) B.(0,2) A.(2,5) :)