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Ad libitum [116K]
3 years ago
15

In remodeling a house an architect finds that by adding the same amount to each dimension of a 15ft by 19ft rectangular room, th

e area would be increased by 98 ft^2. How
much must be added to each dimension?
Let x be the amount that is added to each dimension. After writing an equation in standard form with a > 0, a= ? b= ? and c= ?
(Simplify your answers.)
Mathematics
1 answer:
earnstyle [38]3 years ago
8 0

Answer:

Step-by-step explanation:

new length=15+x

width=19+x

then area=(15+x)×(19+x)=285+15x+19x+x²=x²+34x+285 ft²

original area=15×19=285 ft²

then 285+98=x²+34x+285

or

x²+34x-98=0

x²+34x+17²=98+17²

(x+17)²=98+289=387

x+17=√387=3√43

x=3√43-17 ft

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Karen had 15 snicker bars. she gave 7 to her brother. what percent did she give away
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Step-by-step explanation:

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2 years ago
I really need help with this i beg you !!
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Answer:

The perimeter and area of the square are 56 units and 196 square units, respectively.

Step-by-step explanation:

The inner right triangle represents a 45-45-90 right triangle, which has the feature of a hypotenuse whose length is \sqrt{2} time the length of any of its legs. If the hypotenuse has a measure of 7\sqrt{2}, then the legs of the triangle have a measure of 7.

Now, we are aware that the side length of the square is twice the length of the leg of the right triangle. Then, side length of the square is 14 units long.

Lastly, we know from Geometry that the perimeter and area of the square are represented by the following expressions:

Perimeter

p = 4\cdot l (1)

Area

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p = 4\cdot (14)

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A = 196

The perimeter and area of the square are 56 units and 196 square units, respectively.

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2 years ago
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Answer:

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