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Scorpion4ik [409]
2 years ago
11

Please help i don't know what to do​

Mathematics
1 answer:
Alik [6]2 years ago
4 0

Answer:

The answer is A .

Step-by-step explanation:

Hope it helps u , good luck ^.^

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A six-sided number cube is rolled. Find the probability of rolling a 3 or a number greater than 4. A. 1/18 B. 1/6 C. 1/2 D. 2/3
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The answer is C.1/2 because there is only possible numbers are 3,5,6.
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i really really really need help with this math question i’m giving away FREE points and BRAINLIEST for correct answer
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B is the correct answer. please mark brainliest.

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hopes this helps :]

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Use the discriminant to determine what type of roots the equations will have, and categorize the equations according to their ro
topjm [15]

Step-by-step explanation:

The discriminant of the quadratic equation ax^2+bx+c=0:

\Delta=b^2-4ac

If Δ < 0, then the equation has two complex roots x=\dfrac{-b\pm\sqrt\Delta}{2a}

If Δ = 0, then the equation has one repeated root x=\dfrac{-b}{2a}[/tex If Δ > 0, then the equation has two discint roots [tex]x=\dfrac{-b\pm\sqrt\Delta}{2a}

1.\ x^2-4x+2=0\\\\a=1,\ b=-4,\ c=2\\\\\Delta=(-4)^2-4(1)(2)=16-8=8>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=2\sqrt2\\\\x=\dfrac{-(-4)\pm2\sqrt2}{2(1)}=\dfrac{4\pm2\sqrt2}{2}=2\pm\sqrt2\\\\==============================\\\\2.\ 5x^2-2x+3=0\\\\a=5,\ b=-2,\ c=3\\\\\Delta=(-2)^2-4(5)(3)=4-60=-56

3.\ 2x^2+x-6=0\\\\a=2,\ b=1,\ c=-6\\\\\Delta=1^2-4(2)(-6)=1+48=49>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt{49}=7\\\\x=\dfrac{-1\pm7}{(2)(2)}\\\\x_1=\dfrac{-8}{4}=-2,\ x_2=\dfrac{6}{4}=\dfrac{3}{2}\\\\==============================\\\\4.\ 13x^2-4=0\qquad\text{add 4 to both sides}\\\\13x^2=4\qquad\text{divide both sides by 13}\\\\x^2=\dfrac{4}{13}\to x=\pm\sqrt{\dfrac{4}{13}},\ \bold{two\ distinct\ roots}\\\\==============================

5.\ x^2-6x+16=0\\\\a=1,\ b=-6,\ c=16\\\\\Delta=(-6)^2-4(1)(16)=36-64=-28

7.\ 4x^2+11=0\qquad\text{subtract 11 from both sides}\\\\4x^2=-11\qquad\text{divide both sides by 4}\\\\x^2=-\dfrac{11}{4}\to x=\pm\sqrt{-\dfrac{11}{4}}\\\\x=\pm\dfrac{\sqrt{11}}{2}\ i,\ \bold{two\ complex\ roots}

6 0
3 years ago
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In the figure above, solve for x and y.
Naddik [55]

Answer:

x = 34°

y = 15

Step-by-step explanation:

x + 146 = 180

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9y + 45 = 180

y = 15

5 0
2 years ago
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