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lozanna [386]
3 years ago
15

Natalie reads for 68 hour on 6 days each week.

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
4 0

Answer:

Multiply the time per day by the number of days per week.

6/8 x 6 = (6 x 6)/8 = 36/8 = 4 1/2 hours a week.

Step-by-step explanation:

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X = y - 4<br> -2x + 3y= 6<br> Solve each system by equation
Stella [2.4K]

Answer:

Point form=(-6,-2)

Equation Form= x=-6, y=-2

Step-by-step explanation:

7 0
3 years ago
Marco's painting has an area of 320 square inches. If the width of the painting is 16 inches, what is the length of the length o
Tamiku [17]
If you would like to know what is the length of the painting, you can calculate this using the following steps:

an area = width * length
320 = 16 * length
length = 320 / 16
length = 20 inches

The correct result would be 20 inches.
6 0
3 years ago
Read 2 more answers
What is 791.483 rounded to the nearest whole number?<br><br><br> please help me!!
sveticcg [70]
791 since it has no decimal places
3 0
3 years ago
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
2 years ago
What is the solution to this system 2x + y = 1 3x – y = –6 (–1, 3)
vova2212 [387]

Answer: 2x+y=1

3x-y=-6

==>5x=-5

==>x=-1 and y=1-2*(-1)=3

Sol={(-1,3)}

Answer A

3 0
3 years ago
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