Answer:
The fish population will be in 2050 = 27,123
Step-by-step explanation:
Given,
In 2005, the total number of fish were introduced (fish population), PV = 750
The growth rate, i = 8.3% = 0.083
The difference between 2050 and 2005 is (2050 - 2005), n = 45 years
We need to solve this problem with the help of future value of compounding. We know, FV = PV (1+i)^n, where, PV = present value, i = interest rate, n = period.
Therefore, the fish population will be in 2050 = 750 x (1 + 0.083)^45
The fish population will be in 2050 = 27,123.26
2050 fish population = 27,123 (Nearest to whole number).
