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vovikov84 [41]
3 years ago
7

Learning task 1: find the value of the expression given the value of the variables 3x + 5 x = 2 5xy + x - 4 , x = -3 and y = 5

Mathematics
1 answer:
olasank [31]3 years ago
8 0

Step-by-step explanation:

3x+5x=25xy+x-4

8x=25xy+x-4

8(-3)=25(-3)(5)+(-3-4)

-24=25(-15)+(-7)

-24= -375-7

-24= -382

if the question is right that you asked, i mean the = sign then the solution is will be come like this but if there is no = sign then you can get the solution by subtracting -24-382= -406

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Please help the picture is
asambeis [7]

The walls are vertical so the angle opposite X would be a right angle which is 90 degrees.

X would be 180 - 90 - 35 = 55 degrees

X and 2y - 5 are complementary angles which add together to equal 90:

2y - 5 + 55 = 90

Simplify:

2y +50 = 90

Subtract 50 from both sides:

2y = 40

Divide both sides by 2:

y = 20

7 0
3 years ago
Read 2 more answers
PLEASE HELP NOW!! If K is the set of all letters in the word “equation”, and L is the set of all letters of the word “inequality
satela [25.4K]

Answer:

e,q,u,a,t,i,n & EQUATIONYL

Step-by-step explanation:

K∩L:

First write both the words, equation and inequality down.

E Q U A T I O N

I N E Q U A L I T Y

You can see EQUATIN repeats in both of the words.

K∪L:

First write both the words, equation and inequality down.

E Q U A T I O N

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This time just write down all the letters EXCEPT the ones that repeat. EQUATIONYL

6 0
2 years ago
(1+5i) + (-8+i) ? <br> Need answer and steps
Shtirlitz [24]

Answer:

6\sqrt{-1}-7

Step-by-step explanation:

simplyifying this we get

1+5i-8+i

= 6i-7

I am assuming the i you are talking about here is the sqrt of negative one so that would be 6\sqrt{-1}-7

7 0
3 years ago
The following integral requires a preliminary step such as long division or a change of variables before using the method of par
shtirl [24]

Division yields

\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}

Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}

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which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}

Now, in the integral we get

\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get

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7 0
2 years ago
What is the following product
frosja888 [35]
I would pick C sorry if it’s wrong
3 0
2 years ago
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