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3 years ago

The width of a rectangle is the length minus 6 units the area of the rectangle is 27 units

Mathematics

1 answer:

AleksandrR [38]3 years ago

6 0

Answer:

length = 9 units

Step-by-step explanation:

l = length

n - 6 = width

A = n(n - 6)

A = n² - 6n

27 = n² - 6n

n² - 6n - 27 = 0

(n + 3)(n - 9) = 0

n = -3, n = 9

length must be 9 because it cannot be a negative value

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Step-by-step explanation:

Problem One (left panel)

Question A

The y intercept happens when x = 0
That being said, the y intercept is 50. It was moving when the timing began.

Question B

The rate of change = (56 - 52)/(3 - 1) = 4/2 = 2 miles / hour^2 (you have a slight acceleration.

Question C

60 = a + (n-1)d
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The way I have done it the domain is n from 1 to 6

Question 2 (Right Panel)

Question A

The equation for the table is f(x) = 3x - 3 which was derived simply by putting all three points into y = ax + b and solving.

f(0) = ax + b
-3 = a*0) + b
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f(x) = ax - 3
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3 years ago

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3 years ago

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

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