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Goshia [24]
3 years ago
8

Natasha goes on a trip on her motorcycle and rides for 510 miles. If she rides for 6 hours at a speed of 65 miles per hour, then

at what speed does she travel for the remaining 3 hours of the journey?
Mathematics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

40 miles per hour

Step-by-step explanation:

6 times 65 is 390

510 - 390 = 120

120 divided by 3 is 40

Natasha would have to ride on the motorcycle for the rest of the 3 hours at a speed of 40 per hour.

Hope this helps :)

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8 - 10 is the same as
liubo4ka [24]
B. 8+(-10)


Explanation:

8-10 is -2
If you try all the answers, 8+-10=-2
6 0
3 years ago
5. Find the vertex and length of the latus rectum for the parabola.
olga55 [171]

Answer: (2,5)

Step-by-step explanation:

To find the x coordinate of the vertex, you will set  x-2=0 and solve for x

x-2=0

 +2  +2

x = 2  

Now since we know the vertex has an x coordinate of 2 we have to solve for y by plotting in the x value.

y= 1/2(2-2)^2 + 5

y = 0 +5

y =5

(2,5)

5 0
3 years ago
A researcher is interested in the texting habits of high school students in the United States. The researcher selectsa group of
Aleonysh [2.5K]

Answer:

The population in the study is the entire set of high school students in the United States

Step-by-step explanation:

The goal of the study is to study the texting habits of hogh school students

3 0
3 years ago
A sandwich shop serves 4 ounces of meat and 3 ounces of cheese on each sandwich. After making sandwiches for an hour, the shop o
FromTheMoon [43]

Answer:

Step-by-step explanation:

Given : For each sandwich:

Quantity of meat used = 4 ounces

Quantity of cheese used = 3 ounces

The combined ounces of meat and cheese are used on each sandwich =

Quantity of meat used + Quantity of cheese used

= 4 ounces + 3 ounces

= 7 ounces

Hence, The combined ounces of meat and cheese are used on each sandwich =  7 ounces

8 0
3 years ago
Prove that the roots of x2+(1-k)x+k-3=0 are real for all real values of k​
masha68 [24]

Answer:

Roots are not real

Step-by-step explanation:

To prove : The roots of x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0 are real for all real values of k ?

Solution :

The roots are real when discriminant is greater than equal to zero.

i.e. b^2-4ac\geq 0b

2

−4ac≥0

The quadratic equation x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0

Here, a=1, b=1-k and c=k-3

Substitute the values,

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D=(1-k)^2-4(1)(k-3)D=(1−k)

2

−4(1)(k−3)

D=1+k^2-2k-4k+12D=1+k

2

−2k−4k+12

D=k^2-6k+13D=k

2

−6k+13

D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))

For roots to be real, D ≥ 0

But the roots are imaginary therefore the roots of the given equation are not real for any value of k.

6 0
3 years ago
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