<h3>
Answer: Largest value is a = 9</h3>
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Work Shown:
b = 5
(2b)^2 = (2*5)^2 = 100
So we want the expression a^2+3b to be less than (2b)^2 = 100
We need to solve a^2 + 3b < 100 which turns into
a^2 + 3b < 100
a^2 + 3(5) < 100
a^2 + 15 < 100
after substituting in b = 5.
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Let's isolate 'a'
a^2 + 15 < 100
a^2 < 100-15
a^2 < 85
a < sqrt(85)
a < 9.2195
'a' is an integer, so we round down to the nearest whole number to get 
So the greatest integer possible for 'a' is a = 9.
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Check:
plug in a = 9 and b = 5
a^2 + 3b < 100
9^2 + 3(5) < 100
81 + 15 < 100
96 < 100 .... true statement
now try a = 10 and b = 5
a^2 + 3b < 100
10^2 + 3(5) < 100
100 + 15 < 100 ... you can probably already see the issue
115 < 100 ... this is false, so a = 10 doesn't work
Hello from MrBillDoesMath!
Answer:
@ = pi/3 (or 60 degrees) or @ = 7 pi/3 (or 420 degrees)
Discussion:
Let "@' denote the angle "theta". We are asked to find @ in the interval [0, 4 pi)
where
4cos(@) - 2 = 0. Adding 2 to both sides
4 cos(@) - 2 +2 = 2 =>
4 cos(@) = 2 Divide both sides by 4
cos(@) = 2/4 = 0.5
This implies that @ = pi/3 (or 60 degrees) or @ = (pi/3 + 2pi) = 7 pi/3 (or 420 degrees)
Thank you,
MrB
The answer for this question is 79 :)
To find the length and width of 3 different rectangles that have an area of 48 square inches, you can use the factor pairs that result in 48.
The reason is that to find the area of a rectangle you multiply two dimensions.
2 in x 12 in
3 in x 8 in
4 in x 6 in
On all these either one could be the length and the other the width.
Answer:
Step-by-step explanation:
Given that:
Since the given function is equal to zero, then the function :
where;
and
Thus; f(1) < 0 and f(2) > 0
