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const2013 [10]
3 years ago
9

Suppose ADequalsISubscript m ​(the mtimesm identity​ matrix). Show that for any Bold b in set of real numbers R Superscript m​,

the equation ABold xequalsBold b has a solution.​ [Hint: Think about the equation ADBold bequalsBold b​.] Explain why A cannot have more rows than columns.
Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

See Explanation

Step-by-step explanation:

(a)For matrices A and D, given that: AD=I_m.

We want to show that \forall b \in R^m, Ax=b has a solution.

If Ax=b

Multiply both sides by D

(Ax)D=b \times D\\\implies (AD)x=bD$ (Recall: AD=I_m)\\\implies I_mx=Db $ (Since I_m$ is the m\times m$ identity matrix)\\\implies x=Db

This means that the system Ax=b has a solution.

(b)Matrix A has a pivot position in each row where each pivot is a different column. Therefore, A must have at least as many columns as rows.

This means A cannot have more rows than columns.

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