The bearing of the plane is approximately 178.037°. 
<h3>Procedure - Determination of the bearing of the plane</h3><h3 />
Let suppose that <em>bearing</em> angles are in the following <em>standard</em> position, whose vector formula is:
(1)
Where:
- Magnitude of the vector, in miles per hour.
- Direction of the vector, in degrees.
That is, the line of reference is the 
semiaxis.
The <em>resulting</em> vector (
), in miles per hour, is the sum of airspeed of the airplane (
), in miles per hour, and the speed of the wind (
), in miles per hour, that is:
(2)
If we know that 
, 
, 
and 
, then the resulting vector is:
![\vec v = (7.986, -232.981) \,\left[\frac{mi}{h} \right]](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20%287.986%2C%20-232.981%29%20%5C%2C%5Cleft%5B%5Cfrac%7Bmi%7D%7Bh%7D%20%5Cright%5D)
Now we determine the bearing of the plane (), in degrees, by the following <em>trigonometric</em> expression:
(3)
The bearing of the plane is approximately 178.037°.
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Answer:
direct
Step-by-step explanation:
The standard form of an equation representing direct variation is
y = kx ← k is the constant of variation
The standard form of an equation representing inverse variation is
y = 
← k is the constant of variation
y = - 
x ← represents direct variation with k = -
Answer:
S=1444.4
Step-by-step explanation:
they already gave the formula so
13 is the height, 10 is the radius
plug it in to the formula (using 3.14 for pi)
S=2(3.14)(10)^2+2(3.14)(10)(13)
S=628+816.4
S=1444.4
Answer:
f(- 6) = 70
Step-by-step explanation:
To evaluate f(- 6) , substitute x = - 6 into f(x)
f(- 6) = 2(- 6)² - 2 = 2(36) - 2 = 72 - 2 = 70
