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sertanlavr [38]
3 years ago
6

2(2b+2cd)(2+b) (2a+7)​

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Step-by-step explanation:

The answer to the first one is: 4cd+4b.

The answer to the second one is: 2ab+4a+7b+14

(I'm assuming that you want to simplify)

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Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
4 years ago
What is the solution to the equation below?<br> log 4x2 - log6x = 2
LuckyWell [14K]

Answer: x=2/75

Step-by-step explanation: explanation on photo math app

3 0
3 years ago
Write a formal negation for each of the following statements: a.
AleksAgata [21]

Answer:

See below

Step-by-step explanation:

Let P(x) be a predicate over the variable x. Rules from logic tell us that the negation of ∀xP(x) is ∃x(¬P(x)). That is, the negation operator ¬ satisfies ¬(∀xP(x))≡∃x(¬P(x)). Similarly, ¬(∃xP(x))≡∀x(¬P(x)).

Apply these rules to each statement to obtain:

a) ∃ a fish x, x does not have gills.

b) ∃ a computer c, c does not have a CPU.

c) ∀ movie m, m is not over 6 hours long. ⇔  ∀ movie m, m is under 6 hours long.

d) ∀ band b, b has not won at least 10 Grammy awards. ⇔ ∀ band b, b has  won less than 9 Grammy awards.

5 0
4 years ago
The zeros of this using quadratic equation​
aleksandr82 [10.1K]

Answer:

you have to use the quadratic equation to find the zeros

Step-by-step explanation:

3 0
4 years ago
PLEASE HELP! WILL MARK BRAINLIEST IF YOU'RE CORRECT! IF NOT, NO BRAINLIEST.
Kazeer [188]

Answer:

CYLINDER

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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