Answer:
He traveled for 2.5 hrs at 54 mi/hr
He traveled for 3 hrs at 61 mi/hr
------------------------------
check:
(1) +d+=+54t+
(1) +d+=+54%2A2.5+
(1) +d+=+135+ mi
<em>solution</em>
<em> time taken=100secs</em>
<em> distance covered=500m=0.5km</em>
<em>As we know,</em>
<em> speed=distance covered/time taken</em>
<em> =0.5km/100secs</em>
<em> =0.005km/sec</em>
<h2>
<em> </em></h2><h2>
<em> SPEED IS 0.005KM/SEC</em></h2>
Answer:
It would take 19 hours and 36 minutes until there are 1040 bacteria present.
Step-by-step explanation:
Given that in a lab experiment, 610 bacteria are placed in a petri dish, and the conditions are such that the number of bacteria is able to double every 23 hours, to determine how long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present, the following calculation must be performed:
610X = 1040
X = 1040/610
X = 1.7049
2 = 23
1.7049 = X
1.7049 x 23/2 = X
39.2131 / 2 = X
19.6 = X
100 = 60
60 = X
60 x 60/100 = X
36 = X
Therefore, it would take 19 hours and 36 minutes until there are 1040 bacteria present.
Answer:
23
Step-by-step explanation:
Answer:
√2=1.414
then :√8 +2√32 +3√128+4√50
√8=√2³ =2√2
2√32=√2^5 = 4*2√2 = 8√2
3√128 = 3√2^6*2=8*3√2 =24√2
4√50 =4√5²*2= 20√2
add results : 2√2+8√2 +24√2+20√2=54√2
<h2>
54√2=54×1.414=76.356 ( it is not in the options)</h2>
x=7-4√3
√x+ 1/√x
√(7-4√3) +1/√(7-4√3) =
(8-4√3)/√(7-4√3)
(8-6.93)/√(7-6.93) = 4 ( after rounded to the nearest whole number)
4 is your answer
