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Ymorist [56]
3 years ago
13

In a lab experiment, 610 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to dou

ble every 23 hours. How long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present?​
Mathematics
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

It would take 19 hours and 36 minutes until there are 1040 bacteria present.

Step-by-step explanation:

Given that in a lab experiment, 610 bacteria are placed in a petri dish, and the conditions are such that the number of bacteria is able to double every 23 hours, to determine how long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present, the following calculation must be performed:

610X = 1040

X = 1040/610

X = 1.7049

2 = 23

1.7049 = X

1.7049 x 23/2 = X

39.2131 / 2 = X

19.6 = X

100 = 60

60 = X

60 x 60/100 = X

36 = X

Therefore, it would take 19 hours and 36 minutes until there are 1040 bacteria present.

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Weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. Find the probabi
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Step-by-step explanation:

400÷50= 80 which is the weekly rate of wages

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2 years ago
What is 2 to the 13th power over 8.
Stels [109]
2 to the 13th power = 8192
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Find the slope of the line that passes through (-6, -2) and (-7, -2)
Jobisdone [24]

Answer:

0

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All horizontal lines have a slope of 0 because the value of y never changes as the value of x changes, so if we were to input any two points on a horizontal line into the Slope Formula, our numerator would be 0 (because anything subtracted from itself is 0), leaving us with a result of 0 regardless of the denominator since 0 divided by anything is 0. Hope this helps!

6 0
3 years ago
When dante was born, his grandparents deposited $10,000 into a special college fund that paid 4% annual interest, compounded mon
RSB [31]

Using compound interest, it is found that Dante was 6.6 years old when the balance in the account reached $13,000.

<h3>What is compound interest?</h3>

The amount of money earned, in compound interest, after t years, is given by:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

In which:

  • A(t) is the amount of money after t years.
  • P is the principal(the initial sum of money).
  • r is the interest rate(as a decimal value).
  • n is the number of times that interest is compounded per year.

In this problem, we have that the parameters are given as follows:

A(t) = 13000, A(0) = 10000, r = 0.04, n = 12.

Hence the time in years is found as follows:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

13000 = 10000\left(1 + \frac{0.04}{12}\right)^{12t}

(1.0033)^{12t} = 1.3

\log{(1.0033)^{12t}} = \log{1.3}

12t\log{1.0033} =  \log{1.3}

t = \frac{\log{1.3}}{12\log{1.0033}}

t = 6.6

More can be learned about compound interest at brainly.com/question/25781328

#SPJ1

5 0
2 years ago
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