All categories

2 years ago

Need help plz i show me how to do it plz :)

Mathematics

2 answers:

DaniilM [7]2 years ago

8 0

I’m pretty sure you multiply the sides your you find the formulas for the hight and width

Alex_Xolod [135]2 years ago

8 0

The formula for the surface area of a rectangular prism is SA= 2( (width•length)+(height•length)+(height•width) )

You might be interested in

Please I need help in a rush

baherus [9]

Answer:

i think the answer is 392= 49/Q

3 0

3 years ago

Simplify the radical expression. ⁴√81x²⁰y²⁴<br><br>I think it's either A or B

tangare [24]

Answer:

3x^5y^6 (a)

Step-by-step explanation:

La raiz de un productor es igual al producto de las raices de cada factor

^4√81 ^4√x^20 ^4√y^24

escriba el numero en forma exponencial an base 3

^4√3^4 ^4√x^20 ^4√y^24

simplifica el indice de la raiz y el exponente usando 4

^4√3^4 x^5 ^4√y^24

simplifica el indice de la raiz y el exponente usando 4

^4√3^4 x^5 y^6

simplifica el indice de la raiz y el exponente usando 4

3x^5y^6

7 0

3 years ago

Multiply. <br> -3.9(-5.7)(3) <br> The product is:

scZoUnD [109]

Answer:

66.69

Step-by-step explanation:

You start off with -3.9 x -5.7 which gives you a positive, and that positive is 22.23, then you multiply that number by 3, and you get 66.69.

7 0

3 years ago

Read 2 more answers

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

4 0

2 years ago

The distance from the school to the library is 12 miles. The distance from the school to the park is 75% of this distance.

strojnjashka [21]

75% of 12 can be represented with the equation 75/100=x/12

Then to solve
75(12)= 100x
900 = 100x
9=x

So the distance from the school to the park is 9 miles.

8 0

3 years ago

Read 2 more answers